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3 years ago

Why should knives be washed separately from other dishes?

2 answers:

7 0

The detergents used in dish-washing have chemicals and washing knives in a dishwasher can therefore shorten their lifespan and cutting edge retention.

moreover..it can damage the other utensils as well...

Elena-2011 [213]3 years ago

7 0

If you put knives in the sink along with other dishes you risk reaching for one of the dishes and cutting yourself. And should the dishes and knives collide it could result in broken dishes and dull knives

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Ionic bonds are formed between metal and nonmetal elements. Potassium has only one valence electron and it is stripped away in t

lbvjy [14]

Refer to the table below. Credits to https://terpconnect.umd.edu/~wbreslyn/chemistry/naming/IonicCharge2.jpg

Cations with (+ ) charges lose electrons in order to obtain an octet (8 valence electrons) when they ionically bond with another ion. We're looking for the ions that loses electrons here. So, from the table:

Al 3+ , S 2- , O 2-, Ag + , Ne ( noble gas, no charge)

Since Al and Ag has (+) charges, they are going to lose electrons to form ionic bonds with other atoms.

5 0

4 years ago

Read 2 more answers

For the reaction: CO(g) + H2O(g) â‡Œ CO2(g) + H2(g) the value of Kc is 1.845 at a specific temperature. We place 0.500mol CO and

patriot [66]

Answer:

Explanation:

In the equilibrium:

CO(g) + H₂O(g) ⇄ CO₂(g) + H₂(g)

Kc is:

Kc = 1.845 = [CO₂] [H₂] / [CO] [H₂O]

Where [] are equilibrium concentrations of each species

Initial concentrations:

[CO] = 0.500mol / 1.00L = 0.500M

[H₂O] = 0.500mol / 1.00L = 0.500M

In equilibrium, concentrations will be:

[CO] = 0.500M - X

[H₂O] = 0.500M - X

[CO₂] = X

[H₂] = X

Where X is reaction coordinate. The amount of reactant that reacts producing products.

Replacing in Kc expression:

1.845 = [CO₂] [H₂] / [CO] [H₂O]

1.845 = [X] [X] / [0.500M - X] [0.500M - X]

1.845 = X² / X² - X + 0.25

1.845X² - 1.845X + 0.46125 = X²

0.845X² - 1.845X + 0.46125 = 0

Solving for X:

X = 0.288M; Right solution

X = 1.9M; False solution: Produce negative concentrations.

Replacing, equilibrium concentrations are:

[CO] = 0.500M - X = 0.212M

[H₂O] = 0.500M - X = 0.212M

[CO₂] = X = 0.288M

[H₂] = X = 0.288M

3 0

3 years ago

A compound die will be used to blank and punch a large washer out of aluminum alloy sheet stock 3.2 mm thick. the outside diamet

rodikova [14]

a) The sizes of punch and blanking are equivalent to its diameters. The blanking die diameter is Db = 65 mm

Diameter of the blanking punch is,

dpunch = Db - 2c

Here, c = Ac (thickness)

For aluminium, Ac = 0.06

c = (0.06) (3.2 mm) = 0.192 mm

dpunch = (65 mm) - 2 (0.192 mm)

= 64.616 mm

b) The diameter of the punching punch is equivalent to the interior diameter of the washer.

Thus, diameter of the punching die is, Dh = 30 mm

Diameter of the punching die is,

ddie = Dh + 2c

= (30 mm) + 2 (0.192)

= 30.384 mm

7 0

3 years ago

Tartaric acid is the white, powdery substance that coats sour candies such as sour patch kids. combustion analysis of a 12.01-g

shusha [124]

First we calculate the mass of carbon, hydrogen and oxygen.

Mass of Carbon;
Molar mass of CO₂ is 44.009g/mol and molar mass of C = 12.011 g/mol

Mass of Carbon in 14.08g CO2₂ = 12.011/44.009 x 14.08 = 3.84

Mass Hydrogen;
Molar mass H₂O is 18.0015g/mol and molar mass of H is 1.008and H₂ = 2.016

Mass Hydrogen in 4.32g of H₂O = 2.016/18.0015 x 4.32 = 0.48

Mass of Oxygen = total mas of tartaric acid – (mass of carbon + mass of hydrogen) = 12.01 - (3.84+0.48) = 7.69
Now divide carbon, hydrogen and oxygen through their respective atomic masses: 
C = 3.84/12.011 = 0.32
H = 0.48/1.008 = 0.48
O = 7.69/15.999 = 0.48
Now divide by smallest: 
C = 0.32/0.32 = 1 
H = 0.48/0.32 = 1.5
O = 0.48/0.32 = 1.5
multiply by 2 to get whole integers: 
C = 1 x 2 = 2
H= 1.5 x 2 = 3
O= 1.5 x 2 = 3
Thus, the Empirical formula of tartaric acid = C₂H₃O₃

4 0

3 years ago

How many kilojoules of heat are absorbed when 2.00 L of water is heated from 19*C to 80*C? (Show all work including the equation

Snowcat [4.5K]

Answer:

The answer to your question is 510.7 kJ

Explanation:

Data

Q = ?

Volume = 2 L

Temperature 1 = T1 = 19°C

Temperature 2 = T2 = 80°C

Specific heat = 4.186 J/kg°C

Density of water = 1 g/ml

Equation

Q = mC(T2 - T1)

Process

1.- Calculate the mass of water

mass = density x volume

mass = 1 x 2000

mass = 2000 g

2.- Substitute values in the Heat formula

Q = (2000)(4.186)(80 - 19)

-Simplification

Q = (2000)(4.186)(61)

-Result

Q = 510692 J or 510.7 kJ

7 0

4 years ago