The equations (2) and (3) you referred to are unavailable, but it is clear that you are trying to show that two set of solutions y1 and y2, to a (second-order) differential equation are solutions, and form a fundamental set. This will be explained.
Answer:
SOLUTION OF A DIFFERENTIAL EQUATION.
Two functions y1 and y2 are set to be solutions to a differential equation if they both satisfy the said differential equation.
Suppose we have a differential equation
y'' + py' + qy = r
If y1 satisfies this differential equation, then
y1'' + py1' + qy1 = r
FUNDAMENTAL SET OF DIFFERENTIAL EQUATION.
Two functions y1 and y2 are said to form a fundamental set of solutions to a second-order differential equation if they are linearly independent. The functions are linearly independent if their Wronskian is different from zero.
If W(y1, y2) ≠ 0
Then solutions y1 and y2 form a fundamental set of the given differential equation.
Answer: No Triangle: 30 , 85 , 60, 2,8,10
One Triangle: 7,24,25
Many Triangles: 45,45,90
5,15,160
Step-by-step explanation:
No, they’re not parallel they’re perpendicular if you were to graph them this is what you’d get
Answer:
(f • g) (x) = 
- 3
- 16x - 12
Step-by-step explanation:
(x-6)( + 3x + 2)
+ 3 + 2x - 6 - 18x -12
- 3 - 16x - 12
7 times 0.45 divided by 5 and you get 0.63
Hope this helps you !!
