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Natalija [7]
3 years ago
11

Can someone help me figure out how to graph f(x)=5x-45

Mathematics
1 answer:
tatuchka [14]3 years ago
4 0
Well since the exponent is 1 then the function given is a linear function so y=5x-45 will be a line with a slope of 5 and a y-intercept at (0,-45)
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[ Answer ]

\boxed{\bold{4au^{2} \ - \ 12u^{2} \ + \ aq \ - \ 3q}}

[ Explanation ]

  • Factor: 4u^{2}(a - 3) + q(a - 3)

-------------------------------------

  • Expand 4u^2\left(a-3\right): 4au^2-12u^2

4au^2-12u^2+q\left(a-3\right)

  • Expand

q\left(a-3\right): aq-3q

  • Answer

4au^2-12u^2+aq-3q

\boxed{\bold{[] \ Eclipsed \ []}}

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