What is the length and width of a rectangle if your area is 40 inches and you perimeter is 26 inches
2 answers:
We can write equations, using x and y as the length and width:
xy=40
2x+2y=26
Divide the second equation by two to get:
xy=40
x+y=13
Thus, x=13-y.
We now have (13-x)x=40, so
and
Factoring, we get:
(x-5)(x-8)=0
So, x can be either 5 or 8 (and y will be the other option). Thus, the length and width are 8 and 5.
xy=40
2x+2y=26
Divide the second equation by two to get:
xy=40
x+y=13
Thus, x=13-y.
We now have (13-x)x=40, so
and
Factoring, we get:
(x-5)(x-8)=0
So, x can be either 5 or 8 (and y will be the other option). Thus, the length and width are 8 and 5.
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Answer:
Step-by-step explanation:
First we need to write in correct form :
We know how to divide fractions. If we can divide numerator by numerator, denominator by denominator, we just do it. In this example we can not do that.
So, we rewrite first fraction and multiply by reciprocal second ( numerator and denominator change place)
Now, multiply numerator by numerator, denominator by denominator :