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Klio2033 [76]
3 years ago
15

If you have a compound that directly injects a pair of electrons into complex III of the electron transport chain during aerobic

respiration, the number of protons that can accumulate in the intermembrane space as a result of just this electron pair transfer is
A) 6
B)10
C)12
D)112
E)104
Biology
1 answer:
hammer [34]3 years ago
5 0

Answer:

A) 6

Explanation:

Complex III of the electron transport chain transfers four protons across the membrane during aerobic respiration, per pair of electrons. In the other hand, complex IV is responsible for transporting two protons (per pair of electrons) across the membrane.

If the given compound injects a pair of electron into complex III,  four protons will accumulated due to complex III activity and then two more protons as these electrons move forward to complex IV. This means a total of 6 protons being transported to intermembrane space.

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True or false eukaryotes are much smaller than prokaryotes
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Iron reacts with atmospheric oxygen to form iron oxide or ferric oxide. Look at the chemical equation for this reaction: Fe + O2
Ber [7]

ANSWER

The correct answer is A

<u>EXPLANATION</u>

From the equation Fe + O_2 \rightarrow Fe_2O_3


<u>L.H.S.</u>               


Fe = 1                        

O  =2      

                 

<u> R.H.S</u>

Fe =2


O  =3

Now, let try to balance the oxygen atoms first,

To do this, we know the Least Common Multiples of 2 and 3 is 6


To get 6 atoms of oxygen at L.H.S  multiply 2 by 3 and on the R.H.S, multiply 3 by 2



L.H.S.                        

O=2\times3=6      


R.H.S

O=3\times2=6  


This means that, 3 should be in front of O_2 at the L.H.S and 2 should come before Fe_2O_3 in the R.H.S of the equation


Now, we have


L.H.S.                        


Fe = 1                          

O  =  6                        

<u>R.H.S</u>

Fe =4

O  =6

The equation is still not balanced since Fe is not balance

 

The Least Common Multiple of  1 and 4 is 4

Which means that we need to multiply 1 by 4 at the L.H.S and 4 by 1 at the R.H.S



L.H.S.                        

Fe=1\times4=4      


R.H.S

Fe=4\times1=4  


We now, have



<u>L.H.S.   </u>                    

Fe= 4                          

O=6                        


<u>R.H.S</u>

Fe =4

O=6

Hence the balanced equation is

4Fe +3O_2\rightarrow 2Fe_2O_3




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Answer:

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Explanation:

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