1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alchen [17]
3 years ago
15

Tamara is planting bushes around her house. So far today she has planted 5 bushes and she wants to plant at least 12 bushes toda

y. Which inequality can be used to find the number of bushes (b) Tamara still needs to plant?
Question 4 options:


b+5≥12



b−5≥12



5b≥12



b5≥12
Mathematics
1 answer:
bixtya [17]3 years ago
6 0

Answer:

b+5\geq 12

Step-by-step explanation:

Given:

Number of bushes planted = 5

Minimum number of bushes to be planted = 12

Let the number of bushes planted after planting 5 bushes be b.

Since, Tamara has already planted 5 bushes, total number of bushes planted is given as:

b+5

Now, as per question, total number of bushes should be 12 or greater than 12.

Therefore, b+5\geq 12.

You might be interested in
3x-1/5-2/9x=124/5<br>how do you solve this?
Sergeu [11.5K]
So first you would combine the like-terms so you get:
\frac{7}{9} x - \frac{1}{5} = 124 \div 5
and combine the second like-terms:
\frac{7}{9}x - \frac{1}{5} = 24.8
now you only have a two step equation and you continue by doing the reciprocal and you add the -1/5 to the 24.8 where you get:

7/9x=24.6

then because the 7/9 is being multiplied by the x and your trying to isolate it you divide it by the 7/9 on both sides and you'll end up getting

x=31.628571429....
6 0
3 years ago
Perform the operation and write the answer in simplest form 5 1/7 * 3 1/9
solong [7]

Answer:

16

Step-by-step explanation:

Input it in the calculator

8 0
3 years ago
Read 2 more answers
On the first part of her trip Natalie rode her bike 16 miles and on the second part of the trip she rode her bike 42 miles. Her
-BARSIC- [3]

Answer:

14 mph   ( average speed during the second part of the trip )

Step-by-step explanation:

Let´s call  "x"  the average speed during the first part then

t = 5 hours

t  =  t₁  +  t₂        t₁   and  t₂   times during part 1 and 2 respectively

l = t*v           (  distance is speed by time )      t =  l/v

First part

t₁  = 16/x        and      t₂  = 42 / ( x + 6)

Then

t =   5   =  16/x   +   42 /(x + 6)

5 = [ 16 * ( x  +  6 ) +  42 * x ] / x* ( x + 6 )

5 *x * ( x + 6 )  =  16*x  + 96 +  42 x

5*x² + 30*x  - 58*x - 96  =  0

5*x²  -  28*x  -  96  =  0

We obtained a second degree equation, we will solve for x and dismiss any negative root since negative time has not sense

x₁,₂  =   [28 ± √ (28)² + 1920  ] / 10

x₁,₂  = ( 28  ± √2704 )/ 10

x₁  = 28  -  52 /10        we dismiss that root

x₂  = 80/10

x₂  =  8 mph       average speed during the first part, and the average speed in the second part was 6 more miles than in the firsst part. then the average spedd dring the scond part was 8 + 6 = 14 mph

6 0
3 years ago
Please help ASAP really need this
Aleonysh [2.5K]

Answer:

21.79 + c \leq 25

Joshua can spend up to 3.21 on a card.

Step-by-step explanation:

21.79 + c \leq 25 is the correct equation because Joshua is spending 21.79 on flowers, a certain amount on the card, and the maximum he can spend is 25. That is why you use the less than or equal to sign.

To solve, first subtract 21.79 from both sides to get: c \leq 3.21. This means that Joshua can spend up to 3.21 on a card.

Hope it helps!

3 0
3 years ago
Jason wants to plant 66 carrot seeds and 44 onion bulbs. He would like to plant them so
dexar [7]

The greatest number of plants he can have in each row is 22

He would have 3 rows of carrots

He would have 2 rows of onions

<h3>Greatest Common Factor</h3>

From the question, we are to determine the greatest number of plants he can have in each row

From the given information,

Jason wants to plant 66 carrot seeds and 44 onion bulbs

The greatest number of plants he can have in each row is the greatest common factor of 66 and 44

Factors of 66: 1, 2, 3, 6, 11, 22, 33, and 66

Factors of 44:  1, 2, 4, 11, 22 and 44

The greatest common factor of 66 and 44 is 22

Thus,

The greatest number of plants he can have in each row is 22

He would have 66/22 rows of carrots

66/22 = 3

Thus,

He would have 3 rows of carrots

He would have 44/22 rows of onions

44/22 = 2

Hence, he would have 2 rows of onions

Learn more on Greatest Common Factors here: brainly.com/question/5535901

#SPJ1

3 0
2 years ago
Other questions:
  • Restating the conditions of problem 1, the cost to buy t-shirts is $5.00 for the first 10 shirts, $4.00 for each additional shir
    7·2 answers
  • A model rocket has upward velocity v(t) = 10t2 ft/s, t seconds after launch. Use the interval [0, 6] with n = 6 and equal subint
    14·1 answer
  • Is the set of integers closed under the operation
    12·1 answer
  • the area of the region bounded by the curve y=e^2x the x axis the y axis and the line x=2 is equal toA) e^4/2 -e B) e^4/2 - 1 C)
    12·1 answer
  • Which of the following are congruent? ΔSTV and ΔTVU ST and TV ∠STV and ∠SVT UV and SV ∠U and ∠S ∠TVU and ∠SVT
    5·2 answers
  • 13 points ill also mark brainliest if correct
    15·2 answers
  • Find the indicated length
    5·1 answer
  • The radius R of a sphere is 9.8 cm. Calculate the sphere's surface area A.
    8·1 answer
  • I mark brainliest!
    5·1 answer
  • 37) Kali ran 17 miles less than Alberto last
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!