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Alchen [17]
3 years ago
15

Tamara is planting bushes around her house. So far today she has planted 5 bushes and she wants to plant at least 12 bushes toda

y. Which inequality can be used to find the number of bushes (b) Tamara still needs to plant?
Question 4 options:


b+5≥12



b−5≥12



5b≥12



b5≥12
Mathematics
1 answer:
bixtya [17]3 years ago
6 0

Answer:

b+5\geq 12

Step-by-step explanation:

Given:

Number of bushes planted = 5

Minimum number of bushes to be planted = 12

Let the number of bushes planted after planting 5 bushes be b.

Since, Tamara has already planted 5 bushes, total number of bushes planted is given as:

b+5

Now, as per question, total number of bushes should be 12 or greater than 12.

Therefore, b+5\geq 12.

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How do you simplify (1-x-x^2-x^3)(1-x^4)?
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2 years ago
When we toss a coin, there are two possible outcomes: a head or a tail. Suppose that we toss a coin 100 times. Estimate the appr
marin [14]

Answer:

96.42% probability that the number of tails is between 40 and 60.

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

100 tosses, so n = 100

Two outcomes, both equally as likely. So p = \frac{1}{2} = 0.5

So

E(X) = np = 100*0.5 = 50

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100*0.5*0.5} = 5

Estimate the approximate probability that the number of tails is between 40 and 60.

Using continuity correction.

P(40 - 0.5 \leq X \leq 60 + 0.5) = P(39.5 \leq X \leq 60.5)

This is the pvalue of Z when X = 60.5 subtracted by the pvalue of Z when X = 39.5. So

X = 60.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{60.5 - 50}{5}

Z = 2.1

Z = 2.1 has a pvalue of 0.9821

X = 39.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{39.5 - 50}{5}

Z = -2.1

Z = -2.1 has a pvalue of 0.0179

0.9821 - 0.0179 = 0.9642

96.42% probability that the number of tails is between 40 and 60.

8 0
3 years ago
Could u help me ? I really can’t figure this out it’s driving me crazy
Irina18 [472]

Answer:

1

The answer is 1

One

Un

Uno

Aight nvm

By adding 5 to both side we will just get x2= -4+5

-4+5=1

7 0
3 years ago
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