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3 years ago

12

Mr. Smith lost 10 pounds in one month. At the end of the month, he weighed 240 pounds. What percentage did Mr.Smith decreased he

weighed?
A. 4%
B. 7%
C. 10%
D. 15%

1 answer:

Margaret [11]3 years ago

8 0

Answer:

4%

Step-by-step explanation:

4%=00.4

240+10=250 starting weight

00.4 × 250= 10

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It takes 5 minutes to bake 15 cookies. How many could you bake in 3 minutes

zysi [14]

You could bake 9 cookies in 3 min. 5/15 us equal to 1/3 and 3/9 is equal to 1/3 as well.

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3 years ago

Convert the polar coordinates (-3, -60°) to Cartesian coordinates.

notsponge [240]

Answer:

(1.5,-2.6)

Step-by-step explanation:

Given the polar coordinates (-3,60°).

Let our Cartesian coordinates be (x,y)

#We know that when converting the rectangular coordinates (x,y) to polar (r,θ), then:

$r=\sqrt{x^2+y^2}\\\\\therefore r^2=x^2+y^2\\\\\theta=tan^{-1}(y/x)\\\therefore tan \theta=y/x$

#Using the illustration above, we can express our polar coordinates as:

$-3=\sqrt{x^2+y^2}\\\\-60\textdegree=tan^{-1}(y/x}$

#Solve simultaneously to solve for x and y:

$(-3)^2=x^2+y^2\ \ \ \ \ \ \ \ \ \ i\\\\tan(-0\texdegree)=y/x\ \ \ \ \ \ \ \ ...ii\\\\y=x\ tan(-60\textdegree)\ \ \ \ \ \ \ ...iii\\\\\#substitute\ y \ in\ i\\\\(-3)^2=x^2+(x \ tan (-60\textdegree))^2\\\\9=x^2+3x^2\\\\x=\sqrt{9/4}=1.5\\\\y=1.5\ tan(-60\textdegree)=-2.5981\approx-2.6$

Hence, the Cartesian coordinates are (1.5,-2.6)

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3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

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3 years ago

The table shows how many males and females attended two different movies. How would you find the joint relative frequency of bei

kirza4 [7]

Answer:

B. Divide 124 by 229.

Step-by-step explanation:

Given the table

$\begin{array}{cccc}&\text{Action}&\text{Drama}&\text{Total}\\ \\\text{Male}&105&124&229\\ \\\text{Female}&99&151&250\\ \\\text{Total}&204&275&479\end{array}$

The <u>joint relative frequency</u> is the ratio of the frequency in a particular category and the total number of data values.

The total number of males $=229$

The number of males that like drama $=124$

So, to find the joint relative frequency of being male and attending a drama movie, you should divide 124 by 229.

8 0

3 years ago

Read 2 more answers

Given triangle, ABC is congruent to triangle EDC find A

arlik [135]

Answer:

m<A = 30 degrees.

Step-by-step explanation:

m < C in triangle ABC = m < C in EDC so

x + 13 + 42 + x + 13 = 180

2x = 180 - 13 - 13 - 42

2x = 112

x = 56.

So m < C = 56+13 = 69.

m < B = m < D = 81

M < A = 180 - 69 - 81

= 180 - 150 = 30.

7 0

2 years ago