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2 years ago

Can you solve... 4(-6g-10h)+3h-4(-3h-10g)

Mathematics

1 answer:

andrezito [222]2 years ago

5 0

Answer:

16g - 28h

Step-by-step explanation:

4 ( -6g - 10h ) + 3h - 4 ( -3h - 10g) = -24g - 40h + 3h +12h + 40g

= 16g - 28h

This is pretty simple, all you need to do is distribute the values from the parenthesis and get simplify the variables

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Jaime is 9 years old today. Assume that on every one of his birthdays since

Thepotemich [5.8K]

Answer:

The given statement is False statement

Explanation:

We are given that Jaime has blown out a number of candles equal to his age on each of his birthday till now and he is 9 years old now so the total number of candles blown by him all his life is given by the

arithmetic series

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 and

not the arithmetic series

0 + 1 + 2 + 3+ 4+ 5+ 6+ 7+ 9 as given

so the given statement is false.

6 0

3 years ago

Please answer all the questions above.

Fed [463]

Answer:

hope it was helpful!! You are welcome to ask any question

7 0

3 years ago

Read 2 more answers

Jill has been watching the squirrels that live in her neighborhood. The number of squirrels changes each week. n f(n). 1 8. 2 12

qaws [65]

Answer: D) $f(n)=8(1.5)^{n-1}$

Step-by-step explanation:

From the given table we can see that this is not representing a linear function as the rate of change is not constant.

So it can be exponential growth function $A(b)^{n-1}$ , where A is the initial amount , b is the multiplicative rate of growth and n is the time period in weeks.

Now here at n=1 , f(n)=8

Therefore, A=8

Now, for n=2

$f(2)=8(b)^{2-1}\\\Rightarrow12=8b\\\Rightarrow\ b=\frac{12}{8}\\\Rightarrow\ b=1.5$

By substitute the values of A and b in the above equation, we get the equation $f(n)=8(1.5)^{n-1}$

Therefore, the function best shows the relationship between n and f(n) is

$f(n)=8(1.5)^{n-1}$ , where n is the number of weeks.

7 0

2 years ago

Read 2 more answers

8 pt = __ qt. 7 c = ___ fl oz.

Lisa [10]

8 pt = 4 qt
7c = 56 fl oz

4 0

3 years ago

Simplify the expression x8 y-26/x14 y-5 X x-39 y-21.

KonstantinChe [14]

$\frac{x^8y^{-26}}{x^{14}y^{-5}}[x^{-36}y^{-21}]$

We will apply these following power rule

$x^m*x^n = x^{m+n}$
$x^m/x^n=x^{m-n}$

$[ \frac{x^8}{x^{14}}][ \frac{y^{-26}}{y^{-5}}][x^{-39}y^{-21}]$
$[x^{8-14}][y^{-26-5}][x^{-39}y^{-21}]$
$x^{-6}y^{-21}[x^{-39}y^{-21}]$
$[x^{-6-39}][y^{-21-21}]$
$x^{-45}y^{-42}$

8 0

3 years ago