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mihalych1998 [28]
3 years ago
13

How can i solved ?????????????????????????????

Mathematics
2 answers:
ioda3 years ago
5 0
Paralellogram has 2 pairs of paralell sides

rectangle has 4 right angles and 2 pairs of paralell sides

square has 4 right angles and 2 pairs of paralell sides and 4 equal legnth sides


so
C is a square
B and C are rectangles
A and B and C are paralellograms





alexgriva [62]3 years ago
4 0
1. figure c
2.figure b
3. figure a b and c
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I need to give the slope but I don’t know how someone help!
san4es73 [151]

Answer:

-4/2

Step-by-step explanation:

rise over run

goes down -4 "rises"

moves over 2 runs

7 0
3 years ago
Is 3.14 a rational or irrational
Karolina [17]

Answer:

Rational

Step-by-step explanation:

4 0
3 years ago
Guys help me please ,how to solve it? i need a solution
Ludmilka [50]

Answer:

well, x = 5

Step-by-step explanation:

here,

EB Is parallel to DC , so

Angle AEB = Angle ADE

( because they are corresponding angle pair )

Angle ABE = Angle ACD

( because they are corresponding angle pair )

triangle ADC Is similar to triangle AEB

(By AA similarity criteria )

hence AE / ED = AB / BC ( by CPCT )

so 24/10 = 12/x

=》 24/12= 10/x

=》 x = 5

okay i hope u got it

8 0
3 years ago
If one side of a square notebook measures 20 cm, what is the area of the front cover of the notebook?
jarptica [38.1K]

Answer:

400 cm squared

Step-by-step explanation:

Since a square has all equal sides, this would mean the the all the other sides are 20 as well. To get the area, you would just multiply 20 by 20 to get 400. :)

6 0
3 years ago
Read 2 more answers
After drawing the line y = 2x − 1 and marking the point A = (−2, 7), Kendall is trying to decide which point on the line is clos
igor_vitrenko [27]

Answer:

Step-by-step explanation:

Having drawn the line, Kendall must verify that the point P belongs to the line y = 2x-1 and then calculate the distance between A-P  and verify if it is the closest to A or there is another one of the line

Having the point P(3,5) substitue x to verify y

y=2*(3)-1=6-1=5 (3,5)

Now if the angle formed by A and P is 90º it means that it is the closest point, otherwise that point must be found

d_{AP}=\sqrt{(y_{2}-y_{1})^{2}+(x_{2}-x_{1})^{2}}=\sqrt{(5-7)^{2}+(3-(-2}))^{2}}=\\\sqrt{(-2)^{2}+(5)^{2}}=\sqrt{29}

and we found the distance PQ and QA

; d_{PQ}=\sqrt{125}, d_{QA}=12

be the APQ triangle we must find <APQ through the cosine law (graph 2).

3 0
3 years ago
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