A student took a system of equations, multiplied the first equation by and the second equation by , then added the results toget her. Based on this, she concluded that there were no solutions. Which system of equations could she have started with?
1 answer:
Answer:
option A
-2x + 4y = 4
-3x + 6y = 6
Step-by-step explanation:
In option A, if the student multiply the first equation by 3 and the second equation by -2, then the equations become
-6x+12y = 12 and
6x-12y =-12
If she adds both equations, she will get 0 = 0
This means that the system has infinite number of solutions.
Hence, the student could have started with equations -2x + 4y = 4 and -3x + 6y = 6.
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Step-by-step explanation:
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Answer:
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<u>Given</u>
DE = 3x + 2, EF = x + 5, DF = 23 <u>As per segment addition postulate</u>
<u>Substituting values:</u>
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