Answer:
See Below.
Step-by-step explanation:
Statements: Reasons:
Given
Isosceles Triangle Theorem
Angle Addition
Given
Definition of Bisector
Substitution
Angle Addition
Given
Definition of Bisector
Substitution
Substitution
Division Property of Equality
Reflexive Property
Angle-Side-Angle Congruence*
CPCTC
*For clarification:
∠Y = ∠Z
YZ = YZ (or ZY)
∠PZY = ∠QYZ
So, Angle-Side-Angle Congruence:
ΔYZP is congruent to ΔZYQ
Answer:
6°F
58°F
Step-by-step explanation:
From the data Given :
Temperature rise in Buffalo by noon time = 14°F
The initial temperature at Buffalo = - 8°F
Rise in temperature = 14°F
Therefore, temperature at noon = (-8 + 14)°F = 6°F
B.)
Temperature at 6am in St. Louis = 32°F
Temperature at 6am in Juneau = - 26°F
Temperature difference :
(32 - (-26))°F
32 + 26
= 58°F
Temperature in St. Louis is 58°F higher
Domain: {-4, -2, 0, 2, 4}
range: {-2, -1, 0, 1, 2}
Look at this and you will be surprised on how it helps many like you that’s a key answer
Answer:
8 - 2π square units.
π/16 - 1/8 square units.
6π - 9√3 square units.
Step-by-step explanation:
The area of the square = 2√2 * 2√2
= 2*2*2
= 8.
The area of the circle = πr^2
= π * [ ( 2√2)/ 2) ]^2
= π (√2)^2
= 2π.
Second Question:
The area of the circle = π(1/2)^2 = π/4.
Finding the area of the square:
1^2 = 2x^2
x^2 = 1/2
So the area of the square = 1/2
So the area of the red part = 1/4 ( π/4 - 1/2).
= π/16 - 1/8.
Third question
Area of the circle = 6^2 * π = 36π.
Now 60 degrees is 1/6 of 360 degrees so the are of the sector is 6π.
The area of the segment = 6π - 0.5 * 6^2 sin 60
= 6π - 18√3/2
= 6π - 9√3 square units.
