Step-by-step explanation:
Let the required number be x.
According to the given information:

Hence the required number is 31.
6r 3r
J_______K_______L
--------------27------------
JK + KL = JL
6r + 3r = 27
9r = 27
r = 27/9
r = 3 <=====
Use X1+X2 / 2, Y1+Y2 / 2
-3 + 2 / 2 , -5 + 7 / 2
-1 / 2 , 2/2
(-1/2, 1)
I think this is correct... I know you use the top formula
Answer:
first option
Step-by-step explanation:
Given
f(x) =
← factorise the numerator
=
← cancel (x + 4) on numerator/ denominator
= 2x - 3
Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is
x = - 4
Substitute x = - 4 into the simplified f(x) for y- coordinate
f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11
The discontinuity occurs at (- 4, - 11 )
To obtain the zero let f(x) = 0, that is
2x - 3 = 0 ⇒ 2x = 3 ⇒ x = 
There is a zero at (
, 0 )
Thus
discontinuity at (- 4, - 11 ), zero at (
, 0 )
Answer:
Step-by-step explanation:
y is 15.49
Formula is b = √c^2-a^2
You could use sine [ opposite/hypotenuse ],
Cosine [adjacent/hypotenuse]
or Tangent [ opposite/adjacent ]
to find theta
Theta is 75.522