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iren2701 [21]
3 years ago
13

According to the number line, what is the distance between points A and B? A number line going from negative 16 to positive 12.

A closed circle appears at negative 2 and is labeled A. A closed circle appears at positive 12 and is labeled B. An orange arrow line extends the length of the number line and contains points A and B. 6 units 7 units 12 units 14 units

Mathematics
2 answers:
Anuta_ua [19.1K]3 years ago
7 0

Answer:

6 units

Step-by-step explanation:

On edguenity

DedPeter [7]3 years ago
4 0

Answer: what is the distance between points A and B? 14 Units

Step-by-step explanation: The first thing that you need to do is to draw the number line shown, then we mark the two points mentioned: -2 and 12 and encircle them, following this we are going to count to the right, starting on point A, -2, and finishing on point B, 12. After we count, we are going to see that the distance between the two points is 14 units.

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The power set of Z is

\boxed{2^Z=\bigg\{\{\},\{a\},\{c\},\big\{\{a,b\}\big\},\{a,c\},\big\{a,\{a,b\}\big\},\big\{c,\{a,b\}\big\},\big\{a,c,\{a,b\}\big\}\bigg\}}

1. \{a,c\}\subseteq Z is true because both a\in Z and c\in Z.

2. a\in Z is true.

3. \{c\}\subseteq Z is true (same reason as part 1).

4. \{c\}\in Z is false because Z does not contain the set \{c\}, rather just the element c itself.

5. b\in Z is false because the element b on its own simply is not in Z. That b\in\{a,b\} does not mean b\in Z, but that b belongs to a subset of Z.

6. \{a,b\}\in Z is true.

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3 years ago
Tamara has $42.00 to buy party decorations. She wants to buy 3 packs of party hats, 2 bags of balloons, and a banner
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Step-by-step explanation:

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3 years ago
1.) A. Graph A
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Read 2 more answers
A company wants to find out if the average response time to a request differs across its two servers. Say µ1 is the true mean/ex
lorasvet [3.4K]

Answer:

a) The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0

Test statistic t=0.88

The P-value is obtained from a t-table, taking into acount the degrees of freedom (419) and the type of test (two-tailed).

b)  A P-value close to 1 means that a sample result have a high probability to be obtained due to chance, given that the null hypothesis is true. It means that there is little evidence in favor of the alternative hypothesis.

c) The 95% confidence interval for the difference in the two servers population expectations is (-0.372, 0.972).

d) The consequences of the confidence interval containing 0 means that the hypothesis that there is no difference between the response time (d=0) is not a unprobable value for the true difference.

This relate to the previous conclusion as there is not enough evidence to support that there is significant difference between the response time, as the hypothesis that there is no difference is not an unusual value for the true difference.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that there is significant difference in the time response for the two servers.

Then, the null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0

The significance level is 0.05.

The sample 1, of size n1=196 has a mean of 12.5 and a standard deviation of 3.

The sample 2, of size n2=225 has a mean of 12.2 and a standard deviation of 4.

The difference between sample means is Md=0.3.

M_d=M_1-M_2=12.5-12.2=0.3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{3^2}{196}+\dfrac{4^2}{225}}\\\\\\s_{M_d}=\sqrt{0.046+0.071}=\sqrt{0.117}=0.342

Then, we can calculate the t-statistic as:

t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.3-0}{0.342}=\dfrac{0.3}{0.342}=0.88

The degrees of freedom for this test are:

df=n_1+n_2-1=196+225-2=419

This test is a two-tailed test, with 419 degrees of freedom and t=0.88, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=2\cdot P(t>0.88)=0.381

As the P-value (0.381) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that there is significant difference in the time response for the two servers.

<u>Confidence interval </u>

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=196 has a mean of 12.5 and a standard deviation of 3.

The sample 2, of size n2=225 has a mean of 12.2 and a standard deviation of 4.

The difference between sample means is Md=0.3.

The estimated standard error of the difference is s_Md=0.342.

The critical t-value for a 95% confidence interval and 419 degrees of freedom is t=1.966.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=1.966 \cdot 0.342=0.672

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 0.3-0.672=-0.372\\\\UL=M_d+t \cdot s_{M_d} = 0.3+0.672=0.972

The 95% confidence interval for the difference in the two servers population expectations is (-0.372, 0.972).

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Answer:

C) y=1/4(x - 3)2 - 1

Step-by-step explanation:

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