Answer:
No
Explanation:
It is scientifically impossible.
Answer:
true
Explanation:
cuz it's true also trust me I've done my research.
The Oxidation-Fermentation Test is used to differentiate bacteria built on their capability to oxidize or ferment specific sugars.
Once microbes are inoculated,-One tube is sealed with a layer of sterile mineral oil to promote anaerobic growth and fermentation.-The other tube is left unsealed to allow aerobic growth and oxidation.
Organisms able to ferment the carbohydrate or ferment and oxidize the carbohydrate will turn the sealed and unsealed yellow throughout.
Organisms able only to oxidize the sugar will turn the unsealed yellow medium and leave the sealed medium green or blue.
Fragile fermenters will convert both tubes slightly yellow at the top.
Organisms not able to metabolize the sugar will either produce no color change or will turn the medium blue due to alkaline products from amino acids degradation.
Since Pair #1 showed complete yellowing for sealed and unsealed, these Organisms able to ferment the carbohydrate or ferment and oxidize the carbohydrate. So our interpretation will be that the organism has: Oxidation and fermentation OR fermentation only.
For tubes #2 and #3, the sealed tubes were green throughout suggests that they need oxygen for aerobic growth, and the fact that their unsealed tubes showed light yellowing is evidence for oxidation. Sealed - Green and Unseal - Yellow. Our interpretation for these pairs of tubes would be : Oxidation
Tube 1 can be either Oxidation and fermentation OR fermentation only. So reliability of this needs to be confirmed more with additional testing.
Tubes 2 and 3 are most reliable because they can only be oxidation only and no fermentation.
Answer: Unicellular and microscopic features set the protista apart from the rest of the kingdom.
Explanation:
Protista are eukaryotic organisms that are neither plants, animals or fungi. They do not have a natural group with whom they share common ancestor. They have a unique features that set them apart from the rest of the kingdom which are unicellular and microscopic. Examples are amoeba, blue green algae, diatoms, green algae, ciliates and many more.
Answer:
Explanation:
Given -
Total Population - 
Individuals with homozygous HbA/hbA genotype - 
Individuals with homozygous hbs/hbs genotype -
Individuals with heterozygous hba/hbs genotype - 
Let us assume the given population is in Hardy Weinberg' equilibrium
The frequency of individuals in the given population with homozygous HbA/hba genotype is equal to number of individuals with homozygous HbA/hba genotype divided by total population.
The frequency of hba allele is equal to
