1. The area of a circle is
The area is 9.07 cm^2.
2. The volume of a cube is
The volume is 91.125 m^3
The height of a rectangular pyramid is 30 cm.
volume of rectangular pyramid = (length x width x height) / 3
Given:
Volume = 900 cm³
Length = 10 cm
Width = 9 cm
Height = ?
V = lwh/3
900 cm³ = (10cm * 9cm * h)/3
900 cm³ * 3 = (90cm² * h)/3 * 3
2700 cm³ = 90cm² * h
2700 cm³/90cm² = 90cm² * h/90 cm²
30 cm = h
to check:
900 cm³ = (10 cm * 9 cm * 30 cm)/3
900 cm³ = 2700 cm³/3
900 cm³ = 900 cm³
Answer:
<h3>
A = 0.5(2x+6)(6x+13) = 6x² + 49x + 78</h3>
Step-by-step explanation:
H = 2x+6 - the hight
3H = 3(2x+6) - triple the hight
3H-5 = 3(2x+6) - 5 - five less than triple the height
Area of triangle: A = 0.5BH
B = 3(2x+6)-5 = 6x + 18 - 5 = 6x + 13
H = 2x+6
So:
A = 0.5(2x+6)(6x+13) = (x+6)(6x+13) = 6x² + 13x + 36x + 78
A = 6x² + 49x + 78
A. 1/10000 because it is a 1/100 chance for each.
b. 1/100 because there are 10,000 options and 100 of them are the same options. Simplify for the answer.
Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.
