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Vesnalui [34]
2 years ago
14

I NEED HELP FAST Zane is determining whether the given value of the variable is a solution of the equation.

Mathematics
2 answers:
kotegsom [21]2 years ago
5 0

Answer:the first and the 4th one

Step-by-step explanation:

serg [7]2 years ago
3 0

There are two ways to verify whether the value of ( h ) assumed to be equal to 9 satisfies the given equation:

                          13 + h = 21

                          13 - 13 + h = 21 - 13

                           0 + h = 8

                           h = 8                

                           8 ≠ 9    

 

                          13 + ( 9 ) = 21

                              22 = 21

                              22 ≠ 21

 3) Conclude: The given value of ( h ) is not a solution of the given equation.

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Answer:

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Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

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To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

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y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

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