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3 years ago

I NEED HELP FAST Zane is determining whether the given value of the variable is a solution of the equation.

Mathematics

2 answers:

kotegsom [21]3 years ago

5 0

Answer:the first and the 4th one

Step-by-step explanation:

serg [7]3 years ago

3 0

There are two ways to verify whether the value of ( h ) assumed to be equal to 9 satisfies the given equation:

13 + h = 21

13 - 13 + h = 21 - 13

0 + h = 8

h = 8

8 ≠ 9

13 + ( 9 ) = 21

22 = 21

22 ≠ 21

3) Conclude: The given value of ( h ) is not a solution of the given equation.

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David wants to hang a mirror in his room. The mirror and frame must have an area of 8 square feet. The mirror is 2 feet wide and

hoa [83]

Answer:

4x^2+10x-2=0

Step-by-step explanation:

So the total area of mirror: 2*3 = 6 ft sq

8-6 = 2 ft sq is the area of the frame

x is the thickness of the frame

so we have (2*x)*2+(3*x)*2+x*x*4= 2

4x+6x+4x^2=2

-> 4x^2+10x-2=0

8 0

3 years ago

If f(x)=-5x-11, then f^-1(x)=

Ludmilka [50]

F^-1(x) is the inverse so...
f^-1(x) = (-1/5)x - 11/5

7 0

3 years ago

Tim's credit card has a restriction that he must pay either 15 percent of the unpaid balance or $25, whichever is greater

AveGali [126]

Answer:

He has to pay 15% as that is 32 and more than $25

Step-by-step explanation:

If you take 15% out of 216 it will become 32.

3 0

3 years ago

Read 2 more answers

If you need $8000 to travel to Europe after you graduate in 4 year. How much would your monthly deposits need to be if your acco

lina2011 [118]

$\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\
\left. \qquad \qquad \right.(\textit{payments at the end of the period})
\\\\
A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]$

$\bf \qquad 
\begin{cases}
A=
\begin{array}{llll}
\textit{accumulated amount}\\
\end{array}\to &
\begin{array}{llll}
8000
\end{array}\\
pymnt=\textit{periodic payments}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12\\
t=years\to &4
\end{cases}$

$\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]
\\\\\\
\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt
\\\\\\
\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt$

6 0

3 years ago

K divided by 11 is 7.<br>

sp2606 [1]

Answer:

Step-by-step explanation:

3 0

3 years ago