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pashok25 [27]
2 years ago
5

2x - 5y = -6 -2x + 7y = 14

Mathematics
1 answer:
erastova [34]2 years ago
3 0

Answer:

( 7 , 4 )

Step-by-step explanation:

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Jane paid 40$ for an item after
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after what.................. ???

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PLZ just do it :( 20 points???
Sedaia [141]

The answer would be A, it has no solution

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3 years ago
How many terms are there in a geometric series if the first term is 2, the common ratio is 4, and the sum of the series is 2,730
Furkat [3]

Answer:

n = 6

Step-by-step explanation:

Givens

r = 4

a = 2

Sum = 2730

Equation

Sum = a(1 - r^n)/(1 - r)

Solution

2730 = 2 (1 - 4^n) / (1 - 4)      Reduce the denominator

2730 = 2(1 - 4^n)/-3                Multiply both sides by -3

2730*-3 = 2(1 - 4^n)                Simplify the left

-8190 = 2(1 - 4^n)                    Divide by 2

-8190/2 = 1 - 4^n                     Simplify

-4095 = 1 - 4^n                         Subtract 1 from both sides.

-4096 =  - 4^n                            Divide by - 1

4096 = 4^n                                This looks like n is fairly large. You could use logs. Try n = 6.

4^6 does equal 4096              So your answer is 6.

=========================

Let's try it with logs. Ignore this if you don't know how to do this.

log(4096) = log(4)^n

log(4096) = n*log(4)                    Divide by log 4

log(4096)/log(4) = n

3.6124 / 0.6021  = n

n = 6

========================

The hint is very helpful. Make sure you can follow it through

6 0
3 years ago
Which expression is equivalent to (x superscript one-half baseline y superscript negative one-fourth baseline z) superscript neg
fenix001 [56]

Exponential equations are equation that contain powers or exponents in them. The simplified form of the given expression is \frac{\sqrt{y}}{xz^2}

<h3>Exponential functions</h3>

Given the exponential function expressed as

(x^{1/2}y^{-1/4}z})^{-2}

According to the law of indices expressed as

(a^m)^n= a^{mn}


Applying this law to the given exponential equation, we will have:

=(x^{1/2}y^{-1/4}z})^{-2}\\=(x^{1/2})^{-2}(y^{-1/4})^{-2}(z})^{-2}\\=x^{-1}y^{1/2}z^{-2}

Using the inverse law;

(x^{1/2}y^{-1/4}z})^{-2}=\frac{1}{x}\sqrt{y}\frac{1}{z^2}\\ (x^{1/2}y^{-1/4}z})^{-2}=\frac{\sqrt{y}}{xz^2}

Hence the simplified form of the given expression is \frac{\sqrt{y}}{xz^2}

Learn more on exponential function here: brainly.com/question/14197900

6 0
2 years ago
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