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notsponge [240]
3 years ago
9

Brought 12 grams of chocolate ate half of the chocolate how many grams of chocolate she ate

Mathematics
2 answers:
ratelena [41]3 years ago
8 0
If she ate half it is divided by 2

12 divided by 2 equals 6 so,it is 6 grams of chocolate
NikAS [45]3 years ago
4 0
12 divided by 2 = 6. She ate 6 grams of chocolate.
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3.2*10^2=320 mph

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hello,

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What is the inverse of the function f(x) = 2x + 1?
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Answer:

f^{-1} (x) = \frac{x-1}{2}

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

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4 0
4 years ago
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The bacterial strain Acinetobacter has been tested for its adhesion properties. A sample of five measurements gave read- ings of
oksian1 [2.3K]

Answer:

Part a

We need to conduct a one tailed test

We need to conduct a hypothesis in order to check if the mean is higher than 2.5, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.5  

Alternative hypothesis:\mu > 2.5  

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.372-2.5}{\frac{0.66}{\sqrt{5}}}=2.954    

Part c :P-value

Since is a one sided test the p value would be:  

p_v =P(z>2.954)=0.0016  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, we can conclude that the true mean is higher than 2.5 at 1% of signficance.  

Step-by-step explanation:

a. Should the alternative hypothesis be one-sided or two-sided?

b. Test the hypothesis that the mean adhesion is 2.5 dyne-cm².

c. What is the P-value of the test statistic?

Data given and notation  

Data: 2.69, 5.76, 2.67, 1.62 ,4.12

We can calculate the sample mean with this formula:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

\bar X=3.372 represent the sample mean

\sigma=0.66 represent the population standard deviation

n=5 sample size  

\mu_o =2.5 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a one tailed test

We need to conduct a hypothesis in order to check if the mean is higher than 2.5, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.5  

Alternative hypothesis:\mu > 2.5  

If we analyze the size for the sample is < 30 but we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{3.372-2.5}{\frac{0.66}{\sqrt{5}}}=2.954    

Part c :P-value

Since is a one sided test the p value would be:  

p_v =P(z>2.954)=0.0016  

Conclusion  

If we compare the p value and the significance level assumed \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, we can conclude that the true mean is higher than 2.5 at 1% of signficance.  

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3 years ago
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Ksenya-84 [330]
X=5/27 that should be the right answer
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