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3 years ago

Don’t answer if you don’t know! Your question and account will be reported!

Mathematics

1 answer:

Mkey [24]3 years ago

4 0

Answer:You can divide 54.50 by just 20% with it being 272.5

Step-by-step explanation: You can use it be fraction by dividing it by 20 then you have 2.725 which is the answer.

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8.5 is 50% of what number

zaharov [31]

The answer is going to be 17%. hope that helped

8 0

3 years ago

In a certain year, brand A of heart-rate watch cost $39.99 and brand B cost $59.99. A nonprofit community health organizatio

Oksi-84 [34.3K]

Answer:

Brand A = 21 heart-rate watches.

Brand B = 13 heart-rate watches.

Step-by-step explanation:

Let A be the number of Brand A heart watches and B be the number of Brand B heart watches.

We have been given that a nonprofit community health organization purchased 34 heart-rate watches for use at a wellness center.

We can represent this information in an equation as:

$A+B=34...(1)$

We have been given that in a certain year, brand A of heart-rate watch cost $39.99 and brand B cost $59.99 and the organization spent $1619.66 for the watches.

We can represent this information in an equation as:

$39.99*A+59.99*B=1619.66...(2)$

We will use substitution method to solve our system of equations.

From equation (1) we will get,

$A=34-B$

Substituting $A=34-B$ in equation(2) we will get,

$39.99*(34-B)+59.99*B=1619.66$

$1359.66-39.99*B+59.99*B=1619.66$

$-39.99*B+59.99*B=1619.66-1359.66$

$20*B=260$

$B=\frac{260}{20}$

$B=13$

Therefore, the organisation purchased 13 heart-rate watches of brand B.

Now let us substitute B=13 in equation (1).

$A+13=34$

$A+13-13=34-13$

$A=21$

Therefore, the organisation purchased 21 heart-rate watches of brand A.

8 0

3 years ago

Factor completely 3x4 − 30x3 + 75x2

k0ka [10]

3x^2(x^2-10x+25) hope this helps

5 0

4 years ago

Read 2 more answers

The third-degree Taylor polynomial about x = 0 of In(1 - x) is

gizmo_the_mogwai [7]

Answer:

$\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Functions
Function Notation

Calculus

Derivatives

Derivative Notation

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

MacLaurin/Taylor Polynomials

Approximating Transcendental and Elementary functions
MacLaurin Polynomial: $\displaystyle P_n(x) = \frac{f(0)}{0!} + \frac{f'(0)}{1!}x + \frac{f''(0)}{2!}x^2 + \frac{f'''(0)}{3!}x^3 + ... + \frac{f^{(n)}(0)}{n!}x^n$
Taylor Polynomial: $\displaystyle P_n(x) = \frac{f(c)}{0!} + \frac{f'(c)}{1!}(x - c) + \frac{f''(c)}{2!}(x - c)^2 + \frac{f'''(c)}{3!}(x - c)^3 + ... + \frac{f^{(n)}(c)}{n!}(x - c)^n$

Step-by-step explanation:

*Note: I will not be showing the work for derivatives as it is relatively straightforward. If you request for me to show that portion, please leave a comment so I can add it. I will also not show work for elementary calculations.

Step 1: Define

Identify

f(x) = ln(1 - x)

Center: x = 0

n = 3

Step 2: Differentiate

[Function] 1st Derivative: $\displaystyle f'(x) = \frac{1}{x - 1}$
[Function] 2nd Derivative: $\displaystyle f''(x) = \frac{-1}{(x - 1)^2}$
[Function] 3rd Derivative: $\displaystyle f'''(x) = \frac{2}{(x - 1)^3}$

Step 3: Evaluate Functions

Substitute in center x [Function]: $\displaystyle f(0) = ln(1 - 0)$
Simplify: $\displaystyle f(0) = 0$
Substitute in center x [1st Derivative]: $\displaystyle f'(0) = \frac{1}{0 - 1}$
Simplify: $\displaystyle f'(0) = -1$
Substitute in center x [2nd Derivative]: $\displaystyle f''(0) = \frac{-1}{(0 - 1)^2}$
Simplify: $\displaystyle f''(0) = -1$
Substitute in center x [3rd Derivative]: $\displaystyle f'''(0) = \frac{2}{(0 - 1)^3}$
Simplify: $\displaystyle f'''(0) = -2$

Step 4: Write Taylor Polynomial

Substitute in derivative function values [MacLaurin Polynomial]: $\displaystyle P_3(x) = \frac{0}{0!} + \frac{-1}{1!}x + \frac{-1}{2!}x^2 + \frac{-2}{3!}x^3$
Simplify: $\displaystyle P_3(x) = -x - \frac{x^2}{2} - \frac{x^3}{3}$

Topic: AP Calculus BC (Calculus I/II)

Unit: Taylor Polynomials and Approximations

Book: College Calculus 10e

5 0

3 years ago

David owns a clothes shop on Rolling Street. Which of the following is a statistical question that David can be asked?

valina [46]

Answer:

i would say d.

Step-by-step explanation:

because depending on whether he is a competitor seller go's by the competition prices they might want to know how low is his cheapest shirt they might want to know which one is cheaper, and he would also keep track of his sales

3 0

3 years ago

Read 2 more answers