Select the equation of the line passes through the point (2, 6) and is perpendicular to the line X=4

Apply the distributive property and simplify -6(x+2)=36

Delicious77 [7]

Answer:

-8

Step-by-step explanation:

-6(x+2)=36

-6x-12=36

-6x=48

x=-8

5 0

3 years ago

N equation of a line through (0, 2) which is perpendicular to the line y=3x+3y=3x+3 has slope

zhannawk [14.2K]

Something's not quite right here. What do you mean by "N?"

I could and will make assumptions regarding what you meant. (Feel free to correct me if need be.)

Find the equation of a line through (0,2) which is perpendicular to the line y=3x+3. To find the slope of this perpendicular line, take the negative reciprocal of 3 (the slope of the given line). It is -1/3.

Using the point-slope form of the equation of a straight line:

y = (-1/3)x + 2 (answer)

7 0

3 years ago

Write the expressions for when you translate the graph of y = x+2 a) one unit up, b) one unit down, c) one unit to the left, d)

Aleksandr-060686 [28]

Answers and Step-by-step explanations:

Vertical transformations affect the entire function, while horizontal transformations influence only the x - only the x is altered. Vertical transformations include vertical stretches and shrinks, reflections over the x axis, and translations up and/or down. Horizontal transformations are horizontal stretches and shrinks, reflections over the y axis, and translations left and/or right.

a) "translate one unit up"; since we're translating up, we know this is a vertical translation, which will affect the entire function. So, the function will go from y = x + 2 to y = (x + 2) + 1 or y = x + 3.

b) "translate one unit down"; again, since we're translating down, we know this is another vertical translation, which will affect the entire function. So, our function goes from y = x + 2 to y = (x + 2) - 1 or y = x + 1.

c) "translate one unit to the left"; since we're translating to the left, we know that this will be a horizontal transformation, which will only affect the x. So our function goes from y = x + 2 to y = (x + 1) + 2 or y = x + 3. (Note that "left" will use a "+" sign because horizontal transformations are weird and "backward")

d) "translate one unit to the right"; again, since we're moving to the right, we know this is another horizontal transformation, which will only affect the x. So our function goes from y = x + 2 to y = (x - 1) + 2 or y = x + 1. (Again note that "right" uses "-" instead of "+" as we would think because horizontal transformations are weirdly "backward").

Hope this helps!

6 0

3 years ago

Read 2 more answers

Dorothy is using fabric to cover a photo album the width of the fabric is 5/8 of a yard the area of the fabric is 5/16 square ya

saul85 [17]

For this case we assume that the photo album is rectangular in shape and therefore the fabric too. By definition, the area of a rectangle is given by:

$A = a * b$

Where:

a: It is the length of the rectangle

b: It is the width of the rectangle

According to the problem data we have to:

$b =\frac {5}{8} \yard\\A = \frac {5} {16} \ yards ^ 2$

Substituting:

$\frac {5} {16} = a * \frac {5} {8}$

We clear "a":

$a = \frac {\frac {5} {16}} {\frac {5} {8}}\\a = \frac {5 * 8} {16 * 5}\\a = \frac {8} {16}\\a = \frac {1} {2}$

Thus, the length of the fabric is $\frac {1} {2} yards.$

ANswer:

The length of the fabric is $\frac {1} {2} yards.$

5 0

4 years ago

A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The prem

katrin [286]

Amount of water = 260 gallons

Amount of antifreeze = 60 gallons

Explanation:

let the amount of water = w

amount of water + amount of antifreeze will give 320 gallons of mixture

w + amount of antifreeze = 320

amount of antifreeze = 320 - w ...(1)

The concentration for the antifreeze = 80% = 0.8

The concentration of the mixture = 15% = 0.15

From our question, we are mixing antifreeze with pure water (two different things). In our calculation, we can write the concentration in terms of water or in terms of antifreeze.

Writing the concentration in terms of amount of antifreeze

0.8(amount of antifreeze) + percent of antifreeze (amount of water) = concentraton of the mixture

The mixture contains 15% antifreeze

water contains no antifreeze, percent = 0

0.8(320 - w) + 0(w) = 0.15(amount of mixture)

0.8(320 - w) + 0 = 0.15(320)

256 - 0.8w + 0 = 48

256 - 0.8w = 48

collect like terms:

256 - 48 = 0.8w

208 = 0.8w

divide both sides by 0.8:

208/0.8 = w

w = 260

substitute for w in equation (1)

amount of antifreeze = 320 - 260 = 60

Amount of water = 260 gallons

Amount of antifreeze = 60 gallons

3 0

1 year ago