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3 years ago

Estimate the tip on a $31.77 check using a tip rate of 15%

1 answer:

8 0

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{15\% of 31.77}}{\left( \cfrac{15}{100} \right)31.55}\implies 4.7655$

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A cerise box has a height of 32 centimeters. It has a base with an area of 160 square centimeters. What is the volume, in cubic

Nonamiya [84]

Answer:

5,120 cm³

Step-by-step explanation:

Volume = Base area × height

Base area = 160 cm²

Height = 32 cm

Vol. = 160 × 32

= 5,120 cm³

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3 years ago

Graph by plotting integer points. y = 4 3 x + 3

Allisa [31]

Answer:

x=-3/43

Step-by-step explanation:

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3 years ago

Please answer this correctly

Ksivusya [100]

Answer:

17 teaspoons

Step-by-step explanation:

1 tbs : 3 tsp

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Always start by converting mixed numbers into fractions;

multiply the whole number part by the denominator (under part) of the fraction part and add this to the numerator (upper part);

Then simply apply the ratio.

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3 years ago

How could you use a number line to show that -4 + 3 and -3 + (-4)

Nonamiya [84]

Move negative 4 to the right till you get to positive 3. Then Move negative 3 to the left 4 times

8 0

3 years ago

An instructor in a college class recently gave an exam that was worth a total of 100 points. The instructor inadvertently made t

solniwko [45]

Answer:

B) Method 2 will increase the standard deviation of the students' scores.

Step-by-step explanation:

Given that an instructor in a college class recently gave an exam that was worth a total of 100 points.

The average score for his students was 43 and the standard deviation of the scores was 5 points.

And now he is considering two different strategies for rescaling the exam results of which:

Method 1 = Add 17 points to everyone's score.

Method 2 = Multiply everyone's score by 1.7 .

And we have to check what will be the impact of these methods on the standard deviation of the students' scores.

For this let us consider a simple example to understand this:

Firstly, Formula for calculating Standard Deviation = $\sqrt{\frac{\sum (X-Xbar)^{2}}{n-1}}$

Suppose,

X X - Xbar $(X - Xbar)^{2}$

3 3 - 6 = -3 -3 * -3 = 9

5 5 - 6 = -1 -1 * -1 = 1

10 10 - 6 = 4 4 * 4 = 16

Mean of above data, Xbar = $\frac{3+ 5+10}{3}$ = 6

Standard Deviation of data = $\sqrt{\frac{26}{3-1} }$ = 3.6055

Now let us suppose that we multiply each value of above data with 2 so the new data will be:

X X - Xbar $(X - Xbar)^{2}$

3*2 = 6 6 - 12 = -6 -6 * -6 = 36

5*2 = 10 10 - 12 = -2 -2 * -2 = 4

10*2 =20 20 - 12 = 8 8 * 8 = 64

Mean of new data, Xbar = $\frac{6+ 10+20}{3}$ = 12

Standard Deviation of new data = $\sqrt{\frac{104}{3-1} }$ = 7.2111

Hence, we see that when we multiply any value to the data the standard deviation will increase and in other words it will multiplied by that value which value we multiplied with each data value i.e. when we multiply each data value with 2 the standard deviation also get multiplied by as

3.6055 * 2 = 7.2111

Therefore option B is correct that Method 2 will increase the standard deviation of the students' scores.

And on the other hand Similarly by adding any constant to the data the Standard Deviation will remain same. Therefore Method 1 will have no impact on standard deviation of the students' scores.

8 0

4 years ago