Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
Total friends = 10
Friends from kindergarten = 4
Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1
P(E) = Favourable outcomes / Total outcomes
Probability of getting 1st friend from kindergarten = 4/10
Probability of getting 2nd friend from kindergarten = 3/9
Probability of getting 3rd friend not from kindergarten = 6/8
Since all these probabilities are independent, We can use Multiplicative identity. Thus,
Required probability is 4/10 * 3/9 * 6/8
= 1/10
Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
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Yeah, x= 7/2 and y= -5/2
Please mark as brainliest and I hope this helps
Answer:
so you would replace all r with 2 which is 2+q-2
then replace the q with 6 so it would be: r+6-r
combined both of these to get
2+6-2
which would equal to 6
add the 2 and the 6 to get 8
then subtract 2 to get 6
