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jek_recluse [69]
3 years ago
13

Geometric or arithmetic 4,10,16,22

Mathematics
1 answer:
skad [1K]3 years ago
8 0

Answer:

arithmetic

Step-by-step explanation:

An arithmetic sequence has a common difference d between consecutive terms.

22 - 16 = 6

16 - 10 = 6

10 - 4 = 6

A common difference of 6 exists between consecutive terms.

Thus the sequence is arithmetic.

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1. What would be the depth of water of 3/4 filled rectangular pool, if pool is 10 m long, 7 m wide and 8 m deep?
Vladimir79 [104]

Step-by-step explanation:

Area if the rectangular pool= 10m×7m×8m

= 560m³

3/4 of 560m³

3/4×560

= 420

Hence , the water occupies 420m³ place

7 0
3 years ago
Please look at the screenshot
Lera25 [3.4K]

Answer:

i believe its D

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
1. Find the slope of the line (2,3) and (0,7)
aalyn [17]

Answer:

hope these helps you

Step-by-step explanation:

1. (2,3)&(0,7)

7-3/0-2

4/-2

=-2

2. (0,2)&(5,1)

1-2/5-0

=-1/5

3. (0,0)&(8,1)

1-0/8-0

=1/8

4.(0,2)&(6,4)

4-2/6-0

2/6

= 1/3

5.(0,1)&(4,2)

2-1/4-0

=1/4

6. (-1,6)&(4,2)

2-6/4-(-1)

=-4/5

5 0
4 years ago
Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
3 years ago
What's two subtraction equations to show how to find 15-7
statuscvo [17]
7 less than 15

The difference between 15 and 7

8 0
3 years ago
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