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Vedmedyk [2.9K]
3 years ago
14

What is the value of the x variable in the solution to the following system of equations?

Mathematics
1 answer:
Elden [556K]3 years ago
6 0
-2 (x-2y=-5)

-2x+4y=10
2x+3y=4
0+7y=14
/7. /7
y=2

2x+3 (2)=4
2x+6=4
-6. -6
2x=-2
/2. /2
x=-1

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Write an equation of a line in point-slope and slope intercept form that passes through the point (1, -8) and is perpendicular t
prisoha [69]

Answer:

11y-2x= -90

Step-by-step explanation:

for the point (1,-8)

x=1 and y= -8

for the equation,

2x -4y= -11

x= -1/m

m= -1/x

x = -1/ (-11/2 )

m= 2/11

so for the equation,

y-y1= m(x- x1)

y- -8=2/11(x-1)

11(y+8)= 2(x-1)

11y +88= 2x-2

11y-2x= -90

3 0
3 years ago
Bella used 2/9 of a paper pack, or 72 pieces. How many pieces of paper were there to start with?
prisoha [69]

Hello!

First, we need to find the unit rate.

72 divided by 2 = 36.

36 x 9 = 324.

There were 324 pieces of paper to start with.

Hope this helps, ~Pooch ♥

6 0
3 years ago
To show that TRK= TUK by the SAS postulate, what additional information is necessary?
Anni [7]

Answer:

RTK = UTK

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Given the speeds of each runner below, determine who runs the fastest.
uranmaximum [27]

Answer:

Liz

Step-by-step explanation:

lets make all speeds ft/1sec

Ron 8ft/1sec

Liz 104ft/7sec : 104/7=

14.8571428571 ft/1 sec

Katie

1 mile = 5280ft

5280ft/526sec

5280/526=

10.0380228137ft/1 sec

Emily,

1 min= 60 sec

835ft/60 sec

835/60=

13.9166666667 ft/sec

now, lets order from least to greatest

R:8ft/1sec, K:10.0380228137ft/1 sec,

E:13.9166666667 ft/sec, L:14.8571428571 ft/1 sec

Liz's speed is fastest

4 0
3 years ago
If a 100.8 kg cement bag had 20.35 kg removed from it, what is the new weight of the bag?
Snowcat [4.5K]
Just subtract 20.35 from 100.8
100.8 \: kg - 20.35 \: kg = 80.45 \: kg

if your bag weighs 100.8 kg and you scoop out 20.35 kg then weigh your bag it will be 80.45 bc u took out 20.35 kg of the cement to use. hope that explains it
8 0
3 years ago
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