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3 years ago

How many three-letter permutations

Mathematics

2 answers:

Svetach [21]3 years ago

7 0

Answer:

Step-by-step explanation:

A permutation is a rearrangement of its elements in any sequence or linear order.

We are asked to rearrange the word BEACH into three letter permutations.

We find that each letter represents the first letter 5 x 3 = 15

Then distributes 5 places, so that 15 x 5 = 60

sweet-ann [11.9K]3 years ago

4 0

Answer:

Step-by-step explanation:

nPr=n!/(n-r)!

5!/(5-3)!

(5*4*3*2*1)/(2*1)

120/2

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fgiga [73]

Hopes this helps:

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6 0

2 years ago

Read 2 more answers

Find the product. Simplify using positive exponents. 4⁴ · 4³ 2² · 2⁻⁴

bulgar [2K]

Answer:

Step-by-step explanation:

=4⁴ · 4³

=4^{7}

=16 384

=2² · 2⁻⁴

=2^{-2}

=1/2^{2}

=1/4

5 0

3 years ago

Find a power series representation for the function. (Give your power series representation centered at x = 0.) f(x) = x2/(x4 +

ella [17]

Answer:

Given the function: $f(x) =\frac{x^2}{x^4+16}$

A geometric series is of the form of :

$\sum_{n=0}^{\infty} ar^n$

Now, rewrite the given function in the form of $\frac{a}{1-r}$ so that we can express the representation as a geometric series.

$\frac{x^2}{x^4+16}$

Now, divide numerator and denominator by $x^4$ we get;

$\frac{\frac{1}{x^2}}{1+\frac{16}{x^4}}$ = $\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2}$

Therefore, we now depend on the geometric series which is;

$\frac{1}{1+x} =\sum_{n=0}^{\infty} (-1)^n x^n$

let $x \rightarrow x^2$ then,

$\frac{1}{1+x^2} =\sum_{n=0}^{\infty} (-1)^n x^{2n}$

to get the power series let $x \rightarrow \frac{4}{x^2}$

so,

$\frac{1}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}$

Multiply both side by $\frac{1}{x^2}$ we get;

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\frac{1}{x^2} \cdot \sum_{n=0}^{\infty} (-1)^n (\frac{4}{x^2})^{2n}$

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =x^{-2} \cdot \sum_{n=0}^{\infty} (-1)^n (16)^n (x^{-2})^{2n}$

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n} \cdot x^{-2}$

Using $x^n \cdot x^m = x^{n+m}$

we have,

$\frac{\frac{1}{x^2}}{1+(\frac{4}{x^2})^2} =\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}$

therefore, the power series representation centered at x =0 for the given function is: $\sum_{n=0}^{\infty} (-1)^n (16)^n x^{-4n-2}$

6 0

3 years ago

4. Each set of data was collected from surveys to answer statistical questions. Select all of the data sets that represent numer

Ede4ka [16]

Answer:

Options (A), (C), (D) and (E).

Step-by-step explanation:

There are two types of sets in the given options.

1). Numerical data - Data which shows the numeral values or the numbers which tells the exact meaning of quantities like length, width or height.

2). Categorical data - Data which has no numeral values or no logical order.

Therefore, sets which show the numerical data are,

Option (A)

Option (C)

Option (D)

Option (E)

6 0

4 years ago

Joe earns a monthly salary of 250 plus a commission on his total sales. Last month his total sales were $7,289 and he earned a t

Yakvenalex [24]

Answer: Joe earns a monthly salary of 250 plus a commission on his total sales. Last month his total sales were $7,289 and he earned a total of $1,275. What is his commission rate?

Step-by-step explanation:

250 + $7,289 + $1,275 = 8814

5 0

3 years ago