Answer:
The number of tickets purchased costing $21 each = 18
The number of tickets purchased costing $ 27 each = 11
Step-by-step explanation:
The total number of tickets purchased = 29
Here, let us assume that:
The number of tickets purchased costing $21 = m
The number of tickets purchased costing $ 27 = 29 - m
So, now the cost of m tickets costing $21 each = m x ( $21) = 21 m
Also, the cost of purchasing ( 29-m) tickets costing $27 each
= (29-m)x $27 = 783 - 27 m
Also, the total cost of purchasing 29 tickets = $ 675
⇒ The total cost of m tickets + (29- m ) tickets = $ 675
or, 21 m + 783 - 27 m = 675
⇒ - 6 m = 675 - 783 = -108
or, m 108/6 = 18
⇒ m = 18
Hence the number of tickets purchased costing $21 each = m = 18
The number of tickets purchased costing $ 27 each = 29 - m
= 29 - 18 = 11
