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3 years ago

10.Which of the following is HCF of 2x^2-18 and x^2-2x-3?

Mathematics

1 answer:

Vika [28.1K]3 years ago

7 0

Answer: x - 3

Step-by-step explanation:

Factor:

2x^2 - 18

1. Factor out 2: 2(x^2 - 9)

2.Factor x^2 - 9 into (x-3)(x+3): 2(x - 3)(x + 3)

*Notice that x^2 - a^2 can always be factored into (x-a)(x+a)

where a is a constant so in this case, a is 9 which is also 3^2

so x^2 - 9 can be factored into (x - 3)(x + 3)

x^2 - 2x - 3

1. Think what two numbers multiplied together is -3 and added together is 2

-> 3 and -1 since 3(-1) = -3 and 3+ (-1) = 2

2. Factor x^2 - 2x -3 into (x - 3)(x + 1)

Therefore, since both 2x^2 - 18 and x^2 - 2x -3 do not have another common factor besides x - 3, x - 3 is the HCF of 2x^2 - 18 and x^2 - 2x -3.

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2 years ago

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2 years ago

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wlad13 [49]

we know that

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so, we get

$a(t)=9.8$

and acceleration will always be constant

we know that

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now, we have

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we can use it and find C

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3 years ago

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Verify that the intermediate value theorem applies to the indicated interval and find the value of c guaranteed by the theorem.

Inessa05 [86]

The intermediate value theorem applies to the indicated interval and the importance of c guaranteed by the theorem is c=2,3.

Especially, he has been credited with proving the following five theorems: a circle is bisected via any diameter; the bottom angles of an isosceles triangle are the same; the other (“vertical”) angles are shaped by means of the intersection of two traces are same; two triangles are congruent (of identical form and size.

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2-1

and interval = [4]

since, function fext is continuous in ginen

interval. And also

+(4) = 42+4

4-1

20 = 6667

$(5/4) = ($145/2

stone-1

= 5.833

simle, f(4) > $(5/2), hence Intermediate

Theorem & applies to the indicated

proved.

Now,

= 6

C-1

C-5c +6 = 0

C=2 or c=3

3 or

C= 2, 3

<= 2

Learn more about theorem here brainly.com/question/26594685

#SPJ4

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1 year ago