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3 years ago

Find the value of x.

Mathematics

1 answer:

Colt1911 [192]3 years ago

7 0

Answer:

x = 16 2/3

Step-by-step explanation:

The altitude divides the triangle into similar triangles. We can form the ratio between the hypotenuse and the short leg for two of the triangles. Those ratios will be a proportion:

10/6 = ((x-6) +6)/10

100/6 = x . . . . . multiply by 10 and simplify

x = 16 2/3

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X-5y=-15x−5y=−15x, minus, 5, y, equals, minus, 15 Complete the missing value in the solution to the equation. (-5,(−5,left paren

Y_Kistochka [10]

Answer:

<h2>The missing value is 2. The coordinate will be (-5, 2)</h2>

Step-by-step explanation:

The question is not properly written. Find the correct question below.

If x – 5y = -15 . Complete the missing value in the solution to the equation (-5, ____)

Let the coordinate of the variables be (x, y). Comparing the coordinates (x, y) with the given coordinate (-5, __), we will discover that x = -5. To get the y coordinate, we will substitute x = -5 into the given expression as shown;

If x – 5y = -15

-5 - 5y = -15

Adding 5 both sides

-5-5y+5 = -15+5

-5y = -10

Dividing both sides by -5;

-5y/-5 = -10/-5

y = 2

Hence the missing value in the solution of the equation is 2. The coordinate will be (-5, 2)

3 0

3 years ago

Graph the system of inequalities to show all possible solutions. {y<3x-2 {y ≥ -x+3

Semmy [17]

Answer:

see attachment for graph

Step-by-step explanation:

< or > : dashed line

≤ or ≥ : solid line

< or ≤ : shade below the line

> or ≥ : shade above the line

To graph the line y < 3x-2

Rewrite the equation as: y = 3x - 2

Find two points on the line:

when x = 0, y = 3(0) - 2 = -2 → (0, -2)

when x = 3, y = 3(3) - 2 = 7 → (3, 7)

Plots the found points (0, -2) and (3, 7).

Draw a straight, dashed line through the points.

To graph the line y ≥ -x + 3

Rewrite the equation as: y = -x + 3

Find two points on the line:

when x = 0, y = -(0) + 3 = 3 → (0, 3)

when x = 3, y = -(3) + 3 = 0 → (3, 0)

Plots the found points (0, 3) and (3, 0).

Draw a straight, solid line through the points.

Shade above the solid line and below the dashed line to the right of where the two lines intersect. The shaded area is the area of all possible solutions.