3 years ago

A varies directly as b. If A = 3 when b = 24, find b when A = 10

1 answer:

4 0

240................................ It had to be 20 characters so sorry for the large answer

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scoundrel [369]

Step-by-step explanation:

An arithmetic sequence is given by relation as follows :

$A(n)=-6+(n-1)\dfrac{1}{5}$

For the first term, put n = 1. So,

$A(1)=-6+(1-1)\dfrac{1}{5}\\\\A(1)=-6$

For fourth term, put n = 4. So,

$A(4)=-6+(4-1)\dfrac{1}{5}\\\\A(4)=\dfrac{-27}{5}\\\\A(4)=-5\dfrac{2}{5}$

For tenth term, put n = 10. So,

$A(10)=-6+(10-1)\dfrac{1}{5}\\\\A(10)=-6+\dfrac{9}{5}\\\\A(10)=\dfrac{-21}{5}\\\\A(10)=-4\dfrac{1}{5}$

Hence, the correct option is (C).

7 0

4 years ago

aniked [119]

Sorry it says plus but its times

6 0

4 years ago

Elenna [48]

The value of y = 40.

5x = 40
x = 8

180 = 40 + 40 + (2y + 20)
40 = y

7 0

3 years ago

ivann1987 [24]

26=7v + 5
21=7v
V=21/3
V=3

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3 years ago

Alborosie

10 tables were added

6 0

3 years ago