Question

what is the order from least to greatest - 4 with the exponent of 3, square root of 40, square root of 13, square root of 7, , 14 over 9

Answer 1

Answer: $-4^{3}$ , 14/9 , $\sqrt{7}$ , $\sqrt{13}$ , $\sqrt{40}$

Step-by-step explanation:

$-4^{3}$ = - 64

$\sqrt{40}$ = 6.32455532

$\sqrt{13}$ = 3.605551275

$\sqrt{7}$ = 2.645751311

14/9  = 1.555555556

Arranging from least to greatest , we have :

$-4^{3}$ , 14/9 , $\sqrt{7}$ , $\sqrt{13}$ , $\sqrt{40}$