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FrozenT [24]
3 years ago
11

PLZ HELP MEEEEEE!!! I have a test and i need help plz help me.​

Mathematics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

1.) different, subtract, 14

2.) same, add, -33

3.) same, add, -70

4.) different, subtract, 0

5.) different, subtract, -10

6.) different, add, 12

7.) same, subtract, 3

8.) different, subtract, -4

9.) different, subtract, -4

10.) 14

11.) Mark has more, he has $14 more

12.) 9

13) -13 - 12 = -25

14) 200 - 40 = 60

15) 12 - 3 = 8

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The correct answer is third set of points: <span>A′(6, 10), B′(4, 7), C′(1, 7), D′(1, 11), E′(4, 12) 
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3 years ago
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marysya [2.9K]
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12+ (26-?) = 19 Find The Missing Value.

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3 years ago
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Can someone help me???
chubhunter [2.5K]

Answer: 193.3125

Step-by-step explanation:

It deleted my entire explanation um-

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4 0
3 years ago
Calculate the average rate of change over the interval 2
Morgarella [4.7K]

Answer:

Average rate of change over the interval 2<= x <= 5:

y = 3x + 5:        3

y = 3x^2 + 1:     21

y = 3^x:             78

<u />

Step-by-step explanation:

2<= x <= 5

Average rate of change over the interval 2<= x <= 5:

<u>y = 3x + 5</u>

y(5) = 3(5) + 5 = 20

y(2) = 3(2) + 5 = 11

Average rate of change = (20 - 11)/(5-2) = 9/3 = <u>3</u>

<u />

<u>y = 3x^2 + 1</u>

y(5) = 3(5^2) + 1 = 75 + 1 = 76

y(2) = 3(2^2) + 1= 13

Average rate of change = (76 - 13)/(5-2) = 63/3 = <u>21</u>

<u />

<u>y = 3^x</u>

y(5) = 3^5 = 243

y(2) = 3^2 =9

Average rate of change = (243-9)/(5-2) = 234/3 =<u> 78</u>

8 0
3 years ago
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