Equation in vertex form, y= (-1/4) x² + 4
<u>Step-by-step explanation:</u>
we have the equation,
y = ax² + 4 ( we need to find "a")
Now we have,
2 = a(4)2 + 4
2 = a (8)+ 4
2-4 = 8a
-2= 8a
a= -1/4
Substituting the value of "a" in the equation, we have
y = (-1/4)(x- 0)² + 4 (or) y= (-1/4) x² + 4
The parabola is opens downward. Therefore the vertex is above the x-axis and then the parabola passes through a point below the x-axis.
Equation in vertex form= y= (-1/4) x² + 4
Answer: 0
Step-by-step explanation:
first you distribute the negative which gives you 7-3-4 which equals 0
Answer:
There's nothing there just repost it and don't forget the link
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
If you were to substitute 2 or -3 into equation A, the denominator would be zero and you would have to divide by zero. Thus there are asymptotes for this function at -3 and 2, matching the graph
