Question not well presented
Point S is on line segment RT . Given RS = 4x − 10, ST=2x−10, and RT=4x−4, determine the numerical length of RS
Answer:
The numerical length of RS is 22
Step-by-step explanation:
Given that
RS = 4x − 10
ST=2x−10
RT=4x−4
From the question above:
Point S lies on |RT|
So, RT = RS + ST
Substitute values for each in the above equation to solve for x
4x - 4 = 4x - 10 + 2x - 10 --- collect like terms
4x - 4 = 4x + 2x - 10 - 10
4x - 4 = 6x - 20--- collect like terms
6x - 4x = 20 - 4
2x = 16 --- divide through by 2
2x/2 = 16/2
x = 8
Since, RS = 4x − 10
RS = 4*8 - 10
RS = 32 - 10
RS = 22
Hence, the numerical length of RS is calculated as 22
Answer:
i don't know this type of work.
Step-by-step explanation:
i'm only in 10th grade
Answer:
f(n) = f(n - 1) + 3
Step-by-step explanation:
Substitute 
to get the recursive formula.
OPTION 1: f(n) = f(n - 1) + 3
Substituting n = 1.
f(1) = f(1 - 1) + 3 = 0 + 3 = 3.
Substituting n = 2.
f(2) = f(2 - 1) + 3 = f(1) + 3 = 3 + 3 = 6.
Substituting n = 3.
f(3) = f(3 - 1) + 3 = f(2) + 3 = 6 + 3 = 9.
The numbers match the given sequence. So, we say the above recursive formula represents the sequence.
OPTION 2: f(n) = f(n - 1) + 2
Substituting n = 1
f(1) = f(0) + 2 
3.
So, this is eliminated.
Similarly, OPTION 3 and OPTION 4 can be eliminated as well.
(1,-5) and you start at -5 and go down 1 point over one and then up one over 1
