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AURORKA [14]
2 years ago
7

What is the median of the following salary list $32,019, $21,971, $27,512, $43,702, $38,860, $25,997

Mathematics
2 answers:
mylen [45]2 years ago
3 0

Answer:

$29765.50

Step-by-step explanation:

Median is the middlemost value (or the average of the 2 middlemost value if there are even number of values) in an ascending order.

First, arrange the salary list in an ascending order.

$21,971 , $25,997 , $27,512 , $32,019 , $38,860 , $43,702

As we can see here, there are even number of values (6), so the median will be the average of the 2 middlemost value, which will be:

Median = \frac{27512 + 32019}{2}

= \frac{59531}{2}

= $29765.50

Anestetic [448]2 years ago
3 0

Answer:

$29,765.50 is the median salary

Step-by-step explanation:

To find the median of the following salary list $32,019, $21,971, $27,512, $43,702, $38,860, $25,997

The steps to do this is:

  1. <u>Arrange</u> your numbers in numerical order.
  2. <u>Count</u> how many terms you have.
  3. If you have an <u>odd number</u>, divide by 2 and round up to get the position of the median number.
  4. If you have an <u>even number</u>, divide by 2, go to the number in that position and average it with the number in the next higher position to get the median.

Doing the steps:

  1. $21,971, $25,997, $27,512, $32,019, $38,860, $43,702
  2. 6
  3. does not apply, not odd amount of numbers
  4. 6 / 2 = 3

This means take the average of $27,512 and $32,019

  • $27,512 + $32,019 / 2 = 29,765.50

Learn more about the median here: brainly.com/question/26151333

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Brilliant_brown [7]

Answer:

The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.

Step-by-step explanation:

In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't.  Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype.  However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.  

4 0
3 years ago
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sergij07 [2.7K]

For this case we have the following arithmetic sequence:

a_ {n} = 15 + 5 (n-1)

To write in function form, we apply distributive property to the terms within parentheses:

f (n) = 15 + 5n-5

Different signs are subtracted and the major sign is placed.

We simplify:

f (n) = 5n + 10

Answer:

f (n) = 5n + 10

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