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Novay_Z [31]
4 years ago
6

What is R? i=v/R What is ec? i=ec/3

Mathematics
1 answer:
Juliette [100K]4 years ago
6 0
R would be iv because you have to do cross multiplication.

ec would be 3 because you have to do cross multiplication.

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The isosceles triangle theorem states that if two sides of a triangle are congruent, then the angles those sides are congruent.
inessss [21]

Step-by-step explanation:

option A

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7 0
3 years ago
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Identify the values of the variables. Give your answers in the simplest radical form.
Lena [83]

Answer/Step-by-step explanation:

✔️Find k:

Reference angle = 60°

Hypotenuse = k

Opposite = 9

Therefore, using trigonometric ratio, we have:

sin(60) = \frac{9}{k}

Multiply both sides by k

k*sin(60) = 9

Divide both sides by sin(60)

k = \frac{9}{sin(60)}

k = \frac{9}{\frac{\sqrt{3}}{2}}

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Rationalize

k = \frac{18*\sqrt{3}}{\sqrt{3}*\sqrt{3}}

k = \frac{18\sqrt{3}}{3}

k = 6\sqrt{3}

✔️Find f:

Reference angle = 60°

Opposite = 9

Adjacent = f

Therefore, using trigonometric ratio, we have:

tan(60) = \frac{9}{f}

Multiply both sides by f

f*tan(60) = 9

Divide both sides by tan(60)

f = \frac{9}{tan(60)}

k = \frac{9}{\sqrt{3}}

Rationalize

k = \frac{9*\sqrt{3}}{\sqrt{3}*\sqrt{3}}

k = \frac{9\sqrt{3}}{3}

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8 0
3 years ago
Having trouble with proving Lines Parallel on this page. Help?
snow_tiger [21]
For #1. Step 1: Set the equations equal to one another: (3x + 20) = (2x + 40)

Step 2: Subtract 2x on both sides of the equal sign: (3x-2x + 20) = (2x-2x + 40)

x + 20=40

Step 3: Subtract 20 on both sides of the equal sign: x + 20-20= 40-20

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6 0
4 years ago
Help me please. Show a lil work please.......
Masteriza [31]

Answer:

J) -4.5

Step-by-step explanation:

-12x=54

x=54÷(-12)

x=-4.5

3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=27%3D%281%2F3%29x%2F2%5C%5C" id="TexFormula1" title="27=(1/3)x/2\\" alt="27=(1/3)x/2\\" align=
ICE Princess25 [194]

Answer:

  x = 162

Step-by-step explanation:

The equation editor lets you properly write exponents, so we have to assume that your equation is supposed to be equivalent to ...

  27 = x/6

  27·6 = x = 162 . . . . multiply by 6

_____

On the off chance you intend ...

27=\left(\dfrac{1}{3}\right)^{\dfrac{x}{2}}

you can solve this by taking logarithms and dividing by the coefficient of x. Using base 3 for the logarithm may be easiest.

\log_3{(27)}=\dfrac{x}{2}\log_3{(3^{-1})}\\\\3=-\dfrac{x}{2} \qquad\text{simplify}\\\\-6=x \qquad\text{multiply by -2}

This version of the equation has solution x = -6.

4 0
3 years ago
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