Answer:
The height of the toy is 9 feet after 1 second
Step-by-step explanation:
we have
where
h(t) is the toys height from the ground
t is the time in seconds
so
For t=1 sec
substitute the value of t in the quadratic equation and solve for h(t)
A) The longest horizontal distance is reached at 45 degrees angle. This is true for any projectile launch.
B) First, calculate fligth time (using the vertical motion) and then calculate the horizontal movement.
Flight time = 2* ascendent time
ascendent time => final vertical velocity, Vy, = 0
sin(45) = Voy / Vo => Voy = Vosin(45) = 25.5 m/s * (√2) / 2 = 18.03 m/s
Vy = Voy - gt = 0 => Voy = gt = t = Voy / g
Use g = 10 m/s^ (it is an aproximation, because the actual value is about 9.81 m/s^2 depending on the latitud)
t = 18.03 m/s / 10 m/s^2 = 1.83 s
This is the ascendant time going upward.
The flight time is 2*1.83 = 3.66 s
Horizontal motion
Horizontal velocity = Vx = constant = Vox = Vo*cos(45) = 18.03 m/s
Vx = x / t => x = Vx*t
Horizontal distance = xmax = 18.03m/s*3.66 s = 65.99 m
c) The time the ballon will be in the air was calculated in the part B, it is 18.03 s
Answer:
Step-by-step explanation:
Answer:
The correct answer is the last choice. It travels for 2 hours, then stops for 1 hour, and finally travels again for 2 hours.
Step-by-step explanation:
In the first segment of the trip, the car goes from 0 to 2 hours and the line is moving up. Therefore, it traveled for 2 hours.
In the second segment, the line went straight horizontal for 1 hour. That means the distance didn't change, in other words, it didn't move.
In the last segment, it moved up again for 2 hours.
