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3 years ago

<, >, or =.

Mathematics

2 answers:

laila [671]3 years ago

7 0

Answer:

Step-by-step explanation:

it's -4.4 converted but as it's negative the larger the number the smaller the value

sveticcg [70]3 years ago

6 0

Answer:

Step-by-step explanation:

When it is converted it is -4.4

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Determine 30% of 70. using double number line

Vadim26 [7]

Answer:

100% - 70

---------------------

30% - x

$100x=70*30\\100x=2100\\x=\frac{2100}{100}\\x=21$

3 0

3 years ago

If you earn $15 an hour and you work 35 hours a week, how much do you earn a month?

Ber [7]

2100$ you earn a month because you multiply 15 and 35 and u get 525 then multiply that by 4 since that’s how many weeks are in a month and u get 2100

7 0

3 years ago

What is the range of the function represented by the table of values below?

Viefleur [7K]

The range is the interval of y values.
Smallest y values is -9 and the highest y values is 9.
So the range is $-9 \leq y \leq 9$

4 0

3 years ago

Find the measure of angle A. A 7x-1 12x 489

Degger [83]

Answer:

48 degrees

Step-by-step explanation:

7X-1+12x+48=180

19x+47=180

19x=133

x=7

7(7)-1=A

49-1=A

48=A

A is 48 degrees

7 0

3 years ago

According to the US department of labor, total employment is expected to increase from 146 million in 2000 to 168 million in 201

saveliy_v [14]

Answer:

The percent increase in the employment from the year $2000$ to year $2010$ is $15.07\%$ .

Step-by-step explanation:

Given:

Employment in the year $2000$ $=146$ million.

Employment in the year $2010$ $=168$ million.

To find: The percent increase in the employment.

Solution: We have,

Employment in the year $2000$ $=146$ million.

Employment in the year $2010$ $=168$ million.

Increase in employment $=168-146=22$ million.

Percent increase $=\frac{\textrm{Increase in employment}}{\textrm{Original employment}}\times100\%$

Percent increase $=\frac{22}{146}\times100\%=15.07\%$

Hence, the percent increase in the employment from the year $2000$ to year $2010$ is $15.07\%$ .

3 0

3 years ago