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Luden [163]
3 years ago
5

2(5+(3)(2)+4)

Mathematics
1 answer:
Elza [17]3 years ago
3 0

Answer:

10+5+4+8=27

2(8+6)

=14×2=28

2(8+6

=16+6=22

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How does finding a cure route differ from finding a square root of a positive integer? How do you the answers differ?
Studentka2010 [4]

Answer:

The cube root is the number and 3 of itself times it. The square root it almost the same except it is 2 times.

Step-by-step explanation:

3 0
3 years ago
Four minus the product of one and a number X
densk [106]

Answer:

4 - 1x

Step-by-step explanation:

This could also just be written as 4-x because one times anything is itself, so the one is kinda unnecessary but yup

6 0
3 years ago
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What is the value of x ^2/y^4 when x = 8 and y = 2?​
lawyer [7]

Answer:

64/16=4

Step-by-step explanation:

hope it helps <:)

5 0
3 years ago
What is the prime factorization of 188?
lana66690 [7]
The prime factorization of 188 is 2 x 2 x 47. This is a unique list of the prime factors, along with their multiplicities<span>. Note that the prime factorization of 188 does not include the </span>number<span> 1, yet it does include every instance of a certain prime factor. 188 is a </span>composite number<span>.</span>
6 0
4 years ago
Consider the following set of ages of students is a college seminar.
jonny [76]

Answer:

1) \sum\limits_{i=2}^{6}x_{i}=116

2) \sum\limits_{i=1}^{4}x_{i}=87

Step-by-step explanation:

Given that x_{1}=21,x_{2}=23,x_{3}=22,x_{4}=21,x_{5}=24,x_{6}=26,x_{7}=28

1) Given that \sum\limits_{i=2}^{6}x_{i}

To find  \sum\limits_{i=2}^{6}x_{i}

Expanding the sums below to solve it

\sum\limits_{i=2}^{6}x_{i}=x_{2}+x_{3}+x_{4}+x_{5}+x_{6}  

=23+22+21+24+26 (adding the terms )

=116

Therefore  \sum\limits_{i=2}^{6}x_{i}=116

2) Given that \sum\limits_{i=1}^{4}x_{i}

To find  \sum\limits_{i=1}^{4}x_{i}

Expanding the sums below to solve it

\sum\limits_{i=1}^{4}x_{i}=x_{1}+x_{2}+x_{3}+x_{4}  

=21+23+22+21 (adding the terms )

=87

Therefore  \sum\limits_{i=1}^{4}x_{i}=87

6 0
3 years ago
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