Answer:the car was traveling at a speed of 80 ft/s when the brakes were first applied.
Step-by-step explanation:
The car braked with a constant deceleration of 16ft/s^2. This is a negative acceleration. Therefore,
a = - 16ft/s^2
While decelerating, the car produced skid marks measuring 200 feet before coming to a stop.
This means that it travelled a distance,
s = 200 feet
We want to determine how fast the car was traveling (in ft/s) when the brakes were first applied. This is the car's initial velocity, u.
Since the car came to a stop, its final velocity, v = 0
Applying Newton's equation of motion,
v^2 = u^2 + 2as
0 = u^2 - 2 × 16 × 200
u^2 = 6400
u = √6400
u = 80 ft/s
Answer:
associative property of multiplication
Step-by-step explanation:
You cant rlly explain, you just have to know your properties
If all the power of the variables are greater than or equal to zero, then the expression is a valid polynomial.
So,
1.



are polynomials.
2.

y
2 + s

are all polynomials.
3.
If the degree of the polynomial is 3, then it is a cubic polynomial. If the number of terms of a polynomial is 3, then it is a trinomial.
Hence,
is a cubic trinomial.
4.
The highest power is the degree.
Hence, degree of the polynomial is 2 + 4 = 6.
60 I believe I hope this helps if it was right :)
Answer:
10.5 %
Step-by-step explanation:
Here .
let the Cost Price be 'x'
the..
by the question..
the marked price was fixed to make 30% profit
then..
the marked price will be
x+ 30% of x
= x + 30/100 × x
=x+ 0.3x
=1.3x
soo .. the marked price is 1.3x
now.. after allowing 15% discount..
the selling price will be
1.3x - 15% of 1.3x
= 1.3x - 0.195x
= 1.105x
thank you...
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now..
profit made = 1.105x-x
= 0.105x
soo .
in percentage..
profit percent = profit/cp × 100%
= 0.105x/x × 100%
= 10.5 %