Question

Consider the following set of ages of students is a college seminar.

Answer 1

Answer:

1) $\sum\limits_{i=2}^{6}x_{i}=116$

2) $\sum\limits_{i=1}^{4}x_{i}=87$

Step-by-step explanation:

Given that $x_{1}=21,x_{2}=23,x_{3}=22,x_{4}=21,x_{5}=24,x_{6}=26,x_{7}=28$

1) Given that $\sum\limits_{i=2}^{6}x_{i}$

To find  $\sum\limits_{i=2}^{6}x_{i}$

Expanding the sums below to solve it

$\sum\limits_{i=2}^{6}x_{i}=x_{2}+x_{3}+x_{4}+x_{5}+x_{6}$  

$=23+22+21+24+26$ (adding the terms )

$=116$

Therefore  $\sum\limits_{i=2}^{6}x_{i}=116$

2) Given that $\sum\limits_{i=1}^{4}x_{i}$

To find  $\sum\limits_{i=1}^{4}x_{i}$

Expanding the sums below to solve it

$\sum\limits_{i=1}^{4}x_{i}=x_{1}+x_{2}+x_{3}+x_{4}$  

$=21+23+22+21$ (adding the terms )

$=87$

Therefore  $\sum\limits_{i=1}^{4}x_{i}=87$