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den301095 [7]
3 years ago
8

*NEED HELP ASAP*

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0
X^2 + y^2 - 2x + 7y + 1 = 0


(x^2 - 2x) + (y^2 + 7y) + 1 = 0


(x^2 - 2x + 1) + (y^2 + 7y) + 1 = 0+1


(x^2 - 2x + 1) + (y^2 + 7y + 49/4) + 1 = 0+1+49/4


(x - 1)^2 + (y + 7/2)^2 + 1 = 0+1+49/4


(x - 1)^2 + (y + 7/2)^2 + 1-1 = 0+1+49/4-1


(x - 1)^2 + (y + 7/2)^2 = 49/4


(x - 1)^2 + (y + 7/2)^2 = (7/2)^2


The final answer is choice B
enot [183]3 years ago
7 0

Answer:

The correct option B (x -1)^{2} + (y +\frac{7}{2})^{2} = (\frac{7}{2})^{2}

Step-by-step explanation:

We need to find out the correct option which is similar to the expression;

x^{2} + y^{2}- 2x + 7y + 1 = 0

combine the similar variable together

(x^{2} - 2x) + (y^{2} + 7y) + 1 = 0

Add 1 both the sides,

(x^{2} - 2x + 1) + (y^{2} + 7y) + 1 = 0+1

Add both the sides by \frac{49}{4}

(x^{2} - 2x + 1) + (y^{2} +\frac{49}{4}+ 7y) + 1 = 0+1 + \frac{49}{4}

(x^{2} - 2x + 1) + (y +\frac{7}{2})^{2} + 1 = 0+1 + \frac{49}{4}

Subtract both the sides by 1,

(x^{2} - 2x + 1) + (y +\frac{7}{2})^{2} + 1-1 = 0+1 + \frac{49}{4}-1

(x^{2} - 2x + 1) + (y +\frac{7}{2})^{2} = \frac{49}{4}

(x -1)^{2} + (y +\frac{7}{2})^{2} = (\frac{7}{2})^{2}

This is equivalent to option B

Therefore the correct option B (x -1)^{2} + (y +\frac{7}{2})^{2} = (\frac{7}{2})^{2}

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If k(x) = 5x-6, which expression is equivalent to (k+k) (4)?
goldenfox [79]

Answer:

<em>5(4) - 6 + 5(4) - 6</em>

Step-by-step explanation:

k(x) = 5x - 6

(k+k)(x) = 5x - 6 + 5x - 6

(k+k)(4) = 5(4) - 6 + 5(4) - 6

=> Option D is correct

Hope this helps!

5 0
3 years ago
Please help! I will give points for helpng.
xenn [34]
I think 19 i pretty sure
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Phantasy [73]
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