Hey! First of all, you can express x squared as x^2.
Secondly, the problem! I'm assuming you're asking for the values of x - if you're asking what the equation is, it's a quadratic equation, or a second-degree polynomial. Solving for x, this equation can be factored as (x-4)(x+1)=0. Because either of these two terms being zero will make the whole equation zero, we can have x-4=0, in which case x=4, or x+1=0, in which case x=-1. Therefore, x is either 4 or -1
Given:
2 3/4 cups of tomatoes.
Number of cups of tomatoes written as a fraction greater than one.
2 3/4 is a mixed fraction. It is called such because it is a combination of a whole number and a fraction.
To find the number of cups of tomatoes written as fraction greater than 1, we need to convert the mixed fraction into an improper fraction.
Improper fraction is a fraction whose numerator is greater than its denominator.
2 3/4 ⇒ ((2*4)+3)/4 ⇒ (8+3)/4 ⇒ 11/4
11/4 is a fraction greater than one.
4/4 is a fraction that is equal to one. So, any numerator that is greater than 4 is a fraction that is greater than one. In this case, it is 11/4.
In order to find an average, you have to add all the numbers and divide by the number of things you added.
120.37 + 108.45 + 114.86 = 343.68
343.68/3 = 114.56
She spent an average of $114.56 each month on groceries.
Answer:
The volume of the cylinder = π r² h
where r is the radius of the cylinder and h is the height of the cylinder.
This is formula is applied for the right cylinder as figure 1 and oblique cylinder as figure2.
<u>The volume of the cylinder of figure 1:</u>
r = 6 and h = 7
volume = π r² h = π * 6² * 7 = 252π units³
<u>The volume of the cylinder of figure 2:</u>
r = 11 and h = 15
volume = π r² h = π * 11² * 15 = 1,815π units³
We have an exponential with a fractional base and a positive exponent, and a positive sign at front. Each time we multiply a fraction between zero and one by itself it gets smaller. So as x increases we'll go to zero. As x decreases it goes to positive infinity, as negative powers are the reciprocals of positive power.
The left end approaches positive infinity and the right end approaches zero.
