Geometry, Thanks if you help! question 3

Mathematics

1 answer:

timofeeve [1]3 years ago

5 0

Answer:

Step-by-step explanation:

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

t² + 12² = 13²

t² + 144 = 169 ( subtract 144 from both sides )

t² = 25 ( take the square root of both sides )

t = $\sqrt{25}$ = 5 → A

You might be interested in

What is the degree of 5x^3+3x^2-4x+1? A.) 3 B.) 4 C.) 5 D.) 6

Aleks [24]

When you say degree, do you mean answer if so, there is no solution to this equation.

7 0

3 years ago

Read 2 more answers

Historically, there is a 40% chance of having clear sunny skies in Seattle in July. Let's assume that each day is independent fr

Igoryamba

Answer: a) 0.0058

b) 0.0026

Step-by-step explanation:

Given : The probability of having clear sunny skies in Seattle in July : p= 0.40

The number of days spent in Seattle in July: n= 18

a) Using, Binomial probability formula : $P(x)=^nC_xp^x(1-p)^{n-x}$

The probability of having clear sunny skies on at least 13 of those days:-

$P(x\geq13)=P(13)+P(14)+P(15)+P(16)+P(17)+P(18)\\\\=^{18}C_{13}(0.4)^{13}(0.6)^5+^{18}C_{14}(0.4)^{14}(0.6)^4+^{18}C_{15}(0.4)^{15}(0.6)^3+^{18}C_{16}(0.4)^{16}(0.6)^2+^{18}C_{17}(0.4)^{17}(0.6)^1+^{18}C_{18}(0.4)^{18}(0.6)^0$

$=\dfrac{18!}{13!5!}(0.4)^{13}(0.6)^5+\dfrac{18!}{14!4!}(0.4)^{14}(0.6)^4+\dfrac{18!}{15!3!}(0.4)^{15}(0.6)^3+\dfrac{18!}{16!2!}(0.4)^{16}(0.6)^2+(18)(0.4)^{17}(0.6)^1+(1)(0.4)^{18}$