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tatyana61 [14]
3 years ago
8

The t value for a 95% confidence interval estimation with 24 degrees of freedom

Mathematics
1 answer:
ladessa [460]3 years ago
7 0

Answer:

c. 2.063899

Step-by-step explanation:

Assuming a confidence interval bilateral.

For this case the confidence is 95% so then the significance level is:

\alpha = 1-0.95 =0.05

And \alpha/2 = 0.025

The degrees of freedom are given df = 24 =n-1

So then we need to find a quantile on the t distribution with 24 degrees of freedom that accumulates 0.025 of the area on each tail, and we can use the following excel code:

"=T.INV(1-0.025,24)"

Or equivalently "=T.INV.2T(0.05,24)"

And we got t_{crit}= 2.062899

So the best option is:

c. 2.063899

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