X= 19/12 which is 1.58 in decimal form
Top half:
D (x-2, y+3) E (x-3, y(+\-) 0) F (x+1, y-2)
P (x+1, y+2) Q (x+3, y+4) R (x+5, y+2)
(-a^3b^2*-a^-2b^-3)^-2/2a^2b^-3
= a^4b^9/2a^8b^4
=b^5/2a^4
so your answer is b^5/2a^4
Three and twenty-nine ten-thousandths
Answer: Option d: -3*x^4*y + 2*x^2*y^2 + 5*y^3
Step-by-step explanation:
In standard form, the first term of the polynomial must be the term with the highest degree and on each subsequent term the degree decreases. In the case of two variables, the degree is equal to the sum of the exponents.
Then the correct option is d.
Where the degree of the first term is (4 + 1) = 5
The degree of the second term is (2 + 2) = 4
The degree of the third therm is 3.
We can see that the degree decreases as the term number increases, then the polynomial written in standard form is:
-3*x^4*y + 2*x^2*y^2 + 5*y^3
