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4 years ago

Find the perimeter and area of each rectangle

Mathematics

2 answers:

Alex Ar [27]4 years ago

6 0

Answering From left to right:

alexira [117]4 years ago

4 0

Answer:

1. 40ft

2. 42ft

3. 36ft

4. 20ft

5. 50ft

6. 62ft

7. 38ft

8.50ft

Step-by-step explanation:

add the given numbers and multiply by 2

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Jean and Jericho who are playing in the school grounds decided to sit on a

Natalija [7]

We want to see underline the correct part in each statement.

1) This situation illustrates (direct, inverse) variation.
2) The two quantities that must vary in this situation are (weight and 
distance from the center, height and weight).
3) The heavier the kid, the (closer, farther) he/she should be at the
center to balance the seesaw?
4) When Jean moves farther from the center, Jericho tends to go (up,
down).
5) If Jericho moves closer to the center, Jean tends to go (up, down).

So, Jean and Jericho are playing on a seesaw.

Jean is heavier than Jericho.

Now, notice that a seesaw is a lever. So it "amplificates" the force that you apply in one end to lift the weight that is on the other end. Depending on the form of the lever and the weights, the force that you need to do changes.

If we define:

W₁ = Jean's weight.
d₁ = Jean's distance to the center.
W₂ = Jericho's weight.
d₂ = Jericho's distance to the center.

We must have:

W₁*d₁ = W₂*d₂

Then:

1) This situation illustrates (direct, inverse) variation.

d₁, the position of Jean, varies inversely with respect to Jean's weight.

2) The two quantities that must vary in this situation are (weight and

distance from the center, height and weight).

(by the equation above)

3) The heavier the kid, the (closer, farther) he/she should be at the

center to balance the seesaw?

By the given equation, we see that d₁ must be smaller than d₂.

And the last two are trivial:

4) When Jean moves farther from the center, Jericho tends to go (up,

down).

5) If Jericho moves closer to the center, Jean tends to go (up, down).

If you want to learn more, you can read:

brainly.com/question/18320907

7 0

3 years ago

PLS HELP:

____ [38]

1) At 95% Confidence interval the critical value is z0.025= 1.96 Margin of error = 0.02 Or, z0.025* sqrt(p(1 - p)/n) = 0.02 Or, 1.96 * sqr

6 0

3 years ago

Read 2 more answers

If a triangle is an equilateral triangle, then the triangle has exactly three 60°

ahrayia [7]

Step-by-step explanation:

In an equilateral triangle, all the three sides are equal as well as all the angles are equal. Let the angles be x.

We know that the sum of angles of a triangle is equal to 180 degrees. It means that,

x+x+x=180

3x=180

x=60°

Hence, if a triangle is an equilateral triangle, then the triangle has exactly three 60° angles. Hence, △ABC is an equilateral triangle

3 0

4 years ago

The radius of a circle is (7x+3)cm. Write an expression to represent the area of the circle in simplified form

zepelin [54]

Answer:

A = π(7x + 3)² cm²

Step-by-step explanation:

A = πr² is the appropriate equation. If r = 7x + 3 cm, then the area of this particular circle is:

A = π(7x + 3)² cm²

3 0

3 years ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):