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hram777 [196]
3 years ago
15

Been 3 hours with no answer.

Mathematics
1 answer:
juin [17]3 years ago
4 0

Answer: Fourth option:

v = √( z*(z + w ) )

Step-by-step explanation:

Ok, v is the hypotenuse of the larger triangle, we know, by the Pythagorean's theorem, that:

v = √(y^2 + z^2)

now, in the smaller triangle we have that:

x = √(y^2 + w^2)

And we also know that:

z + w = √(x^2 + v^2)

(z + w)^2 = x^2 + v^2

and x^2 = (y^2 + w^2)

(z + w)^2 = z^2 + w^2 + 2*z*w = y^2 + w^2 + v^2

v = √( z^2 + w^2 + 2*z*w - y^2 - w^2)

v = √( z^2 + 2*z*w - y^2 )

and y is the altitude of the larger triangle rectangle, so, by the geometric mean theorem, we have that:

y^2 = z*w

v = √( z^2 + 2*z*w - z*w ) = √( z^2 + z*w  ) = √( z*(z + w ) )

The correct option is the fourth one.

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false

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let's say we have two odd numbers

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(2k+1)(2t+1)\\\\=4kt+2k+2t+1\\\\=2(2kt+k+t)+1

so we see it's odd

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Answer:

\angle PQR, \angle SQR, and \angle PQS

Or

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Step-by-step explanation:

The three different angles in the diagram are angle PQR, angle SQR and angle PQS.

Another way of writing this is using an angle sign before the alphabets follows. Thus:

\angle PQR, \angle SQR, and \angle PQS

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3 years ago
Given the equation 4x2 − 8x 20 = 0, what are the values of h and k when the equation is written in vertex form a(x − h)2 k = 0?
Westkost [7]

The vertex form of the given quadratic equation is

4(x-1)^{2} + 16 =0.

According to the given question.

We have a quadratic equation

4x^{2} -8x + 20 = 0

Since, for the standard quadratic form is ax^{2} +bx + c = y, the vertex form of a quadratic equation is y = a(x -h)^{2} + k where (h, k) is the vertex.    

And h and k can be calculated as

h = -b/2a and y = k

So, for the given equation 4x^{2} -8x + 20 =0 the vertex (h, k) is given by

h = -(-8)/2(4) = 8/8 = 1   (X coordinate of vertex)

and,

y =4x^{2} -8x+ 20

substitute x = 1 in the above equation for the value of k

Y = 4(1)(1) - 8(1) + 20

⇒ Y = 4 - 8 + 20

⇒ Y = -4 + 20

⇒ Y = 16

so, k = 16          (Y coordinate of vertex)

Now, substitute the value of a, k and h in y = a(x-h)^{2} + k.

⇒  0 =4(x-1)^{2} + 16

Therefore, the vertex form of the given quadratic equation is

4(x-1)^{2} + 16 =0.

Find out more information about vertex form of a quadratic equation here:

brainly.com/question/12223454

#SPJ4

6 0
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