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galina1969 [7]
3 years ago
7

If 11 oranges cost $2.35, what is the cost of 18

Mathematics
1 answer:
Nastasia [14]3 years ago
6 0

Answer:

$3.8

Step-by-step explanation:

2.35/11=0.2136

0.2136*18=3.8448

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Pablo tiene $150 pesos, se gastó la tercera parte de su dinero el domingo, y el lunes se gastó las 2/5
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Answer:

Step-by-step explanation:

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2 years ago
64 = 4(p + 2) + 24 please solve step by step
Wittaler [7]

Answer:

8

Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant   1 • -16 = -16

Step-2 : Find two factors of  -16  whose sum equals the coefficient of the middle term, which is   6 .

     -16    +    1    =    -15

     -8    +    2    =    -6

     -4    +    4    =    0

     -2    +    8    =    6    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  8

                    p2 - 2p + 8p - 16

Step-4 : Add up the first 2 terms, pulling out like factors :

                   p • (p-2)

             Add up the last 2 terms, pulling out common factors :

                   8 • (p-2)

Step-5 : Add up the four terms of step 4 :

                   (p+8)  •  (p-2)

            Which is the desired factorization

3 0
3 years ago
Read 2 more answers
A jar of salsa costs $0.95. Neha bought 9 jars of salsa. How much did Neha spend in all? <br><br> $
olga2289 [7]

Answer:

$8.55

Step-by-step explanation:

$0.95 x 9 jars = $8.55

For every jar Neha buys, she spends $0.95, and buying 9 jars in total, she pays $8.55 in total.

5 0
3 years ago
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What value of d makes the equation 5d-3=2d+6 true?<br><br><br>I NEED HELP WITH THIS ASAP
Annette [7]

Answer:

the answer for this question is 3

5 0
3 years ago
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In the production of a plant, a treatment is being evaluated to germinate seed. From a total of 60 seed it was observed that 37
djyliett [7]

Answer:

More than 50% would germinate

Step-by-step explanation:

Given that in the production of a plant, a treatment is being evaluated to germinate seed. From a total of 60 seed it was observed that 37 of them germinated

Let us check whether more than 50% will germinate using hypothesis test

H_0: p = 0.50\\H_a: p>0.50\\

(right tailed test)

Sample proportion p =\frac{37}{60} =0.617\\q = 0.383\\Std error = \sqrt{\frac{pq}{n} } =0.0628

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Test statistic Z = p difference/std error = 1.864

p value =0.0312

Since p value <0.05 our significance level of 5% we reject null hypothesis

It is  possible to claim that most of the seed will germinate (i.e. more than 50%)

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3 years ago
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