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Shkiper50 [21]
3 years ago
9

The function A(b) relates the area of a trapezoid with a given height of 12 and

Mathematics
1 answer:
Flura [38]3 years ago
5 0

Answer:

B(a)=\frac{a}{6}-9

Step-by-step explanation:

see the attached figure , to better understand the problem

we have

A(b)=12(\frac{b+9}{2})

where

A(b) ---> is the trapezoid's area

b ---> is the other base value

Solve the equation for b

That means ----> isolate the variable b

Divide 12 by 2 right side

A=6(b+9)

Divide by 6 both sides

\frac{A}{6}=b+9

subtract 9 both sides

\frac{A}{6}-9=b

Rewrite

b=\frac{A}{6}-9

Convert to function notation

B(a)=\frac{a}{6}-9

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The probability that a lab specimen contains high levels of contamination is 0.10. A group of 4 independent samples are checked.
galben [10]

Answer:

a) 0.6561

b) 0.2916

c) 0.3439    

Step-by-step explanation:

We are given the following information:

Let us treat high level of contamination as our success.

p = P(High level of contamination) = P(success) = 0.10

n = 4

The, by binomial distribution:

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}\\\text{where x is the number of success}

a) P(No high level of contamination)

We put x = 0, in the formula.

P(X=0) = \binom{4}{0}.(0.10)^0.(1-0.10)^{4} =0.6561

Probability that no lab specimen contain high level of contamination is 0.6561

b) P(Exactly one high level of contamination)

We put x = 1, in the formula.

P(X=1) = \binom{4}{1}.(0.10)^1.(1-0.10)^{3} =0.2916

Probability that no lab specimen contain high level of contamination is 0.6561

c) P(At least one contains high level of contamination)

p(x \geq 1) = 1 - p( x = 0) = 1 - 0.6561 = 0.3439

Probability that at least 1 lab specimen contain high level of contamination is 0.3439

8 0
3 years ago
1) 14, 16, 18, 20, 22, ...<br> A) 29, 32, 35 B) 24, 26, 28<br> C) 34, 38, 42 D) 28, 31, 34
sergij07 [2.7K]

Answer:

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4 0
2 years ago
Which of the following is in the solution set of y&lt; 8 x− 3? Select one: (7, 46) (7, 60) (10, 89) (9, 82)
navik [9.2K]

Answer:

  (7, 46)

Step-by-step explanation:

The offered answer choices have x-values of 7, 9, 10. The corresponding upper limit of y-value is ...

  x=7 : y < 8·7 -3 = 53 . . . . . 46 is in the solution set, 60 is not

  x=9 : y < 8·9 -3 = 69 . . . . 82 is not in the solution set

  x=10 : y < 8·10 -3 = 77 . . . . 89 is not in the solution set

Of the choices offered, only (7, 46) is in the solution set.

3 0
3 years ago
What is the solution to 31|-3x + 9|=-18
Kisachek [45]

Answer:

No solutions

Step-by-step explanation:

31 times any positive number cannot be a negative number.

8 0
3 years ago
Find the center and radius of the with the equation (x + 5) ^ 2 + (y - 2) ^ 2 = 25
iVinArrow [24]

Answer: Center: (5,0)

Radius:5

Step-by-step explanation: Happy to help :)

8 0
3 years ago
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