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goblinko [34]
3 years ago
14

Need help for question 8 and 9. I need the equation that’s passes through the points!

Mathematics
1 answer:
dsp733 years ago
4 0

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = \frac{y_2-y_1}{x_2-x_1}

For two points (1, 4) and (5, 8),

m = \frac{8-4}{5-1}

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = \frac{y_2-y_1}{x_2-x_1}

For two points (2, 10) and (6, 4)

m = \frac{10-4}{2-6}

m = -\frac{3}{2}

By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

Since, this line passes through (2, 10)

10 = -\frac{3}{2}(2)+b

b = 10 + 2

b = 12

Therefore, equation of the line will be,

y=-\frac{3}{2}x+12

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Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.Tiles
Ugo [173]

By definition, the average rate of change is given by:

AVR = \frac{f(x2)-f(x1)}{x2-x1}

We evaluate each of the functions in the given interval.

We have then:

For f (x) = x ^ 2 + 3x:

Evaluating for x = -2:

f (-2) = (-2) ^ 2 + 3 (-2)\\f (-2) = 4 - 6\\f (-2) = - 2

Evaluating for x = 3:

f (3) = (3) ^ 2 + 3 (3)\\f (3) = 9 + 9\\f (3) = 18

Then, the AVR is:

AVR = \frac{18-(-2)}{3-(-2)}

AVR = \frac{18+2}{3+2}

AVR = \frac{20}{5}

AVR = 4


For f (x) = 3x - 8:

Evaluating for x =4:

f (4) = 3 (4) - 8\\f (4) = 12 - 8\\f (4) = 4

Evaluating for x = 5:

f (5) = 3 (5) - 8\\f (5) = 15 - 8\\f (5) = 7

Then, the AVR is:

AVR = \frac{7-4}{5-4}

AVR = \frac{3}{1}

AVR = 3


For f (x) = x ^ 2 - 2x:

Evaluating for x = -3:

f (-3) = (-3) ^ 2 - 2 (-3)\\f (-3) = 9 + 6\\f (-3) = 15

Evaluating for x = 4:

f (4) = (4) ^ 2 - 2 (4)\\f (4) = 16 - 8\\f (4) = 8

Then, the AVR is:

AVR = \frac{8-15}{4-(-3)}

AVR = \frac{-7}{4+3}

AVR = \frac{-7}{7}

AVR = -1


For f (x) = x ^ 2 - 5:

Evaluating for x = -1:

f (-1) = (-1) ^ 2 - 5\\f (-1) = 1 - 5\\f (-1) = - 4

Evaluating for x = 1:

f (1) = (1) ^ 2 - 5\\f (1) = 1 - 5\\f (1) = - 4

Then, the AVR is:

AVR = \frac{-4-(-4)}{1-(-1)}

AVR = \frac{-4+4}{1+1}

AVR = \frac{0}{2}

AVR = 0


Answer:

from the greatest to the least value based on the average rate of change in the specified interval:


f(x) = x^2 + 3x interval: [-2, 3]

f(x) = 3x - 8 interval: [4, 5]

f(x) = x^2 - 5 interval: [-1, 1]

f(x) = x^2 - 2x interval: [-3, 4]


4 0
3 years ago
I need helpppppppp!!!!!!!!!!!!
Anna007 [38]
EF(g) corresponds HJ(i)
FG(e) corresponds JI(h)
GE(f) corresponds IH(j)
(h/e)*f=(23.4/11.7)*13.05=26.1
Answer C: 26.1
7 0
3 years ago
In the first 9 basketball games Lashonda scores 114 points (about 13 points per game), at this rate how many points will Lashond
marishachu [46]

312

24 x 13 = 312

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6 0
4 years ago
Neeeed helppp been stuck on this lesson for too long
Norma-Jean [14]

Answer:

substitude (2x+4) for y in the second equation

 

7 0
4 years ago
Read 2 more answers
Bag A has 20% more red balls than bag
Crank

Answer:

50

Step-by-step explanation:

Let a = number of balls in bag A.

Let b = number of balls in bag B.

a = 1.2b

a - 5 = b + 5

1.2b - 5 = b + 5

0.2b = 10

b = 50

Answer: 50

3 0
3 years ago
Read 2 more answers
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