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AnnyKZ [126]
2 years ago
7

Can somebody help me with this please!!

Mathematics
1 answer:
saul85 [17]2 years ago
8 0

1. -21

2. −39

3.−42

4. -5

5. −3

for the other question u can use calculator :)

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Nicole made costumes for the annual school play. She used a total length of 1468.8 in of blue fabric. The fabric came in 3 rolls
Charra [1.4K]
1468.8/3 = 489.3 in
convert answer into yards (divide by 36)
there was 13.6 yards of fabric in each roll.
5 0
2 years ago
Mr. Clifton was preparing for his upcoming birthday party. He ordered 51 white balloons and 47 red balloons. As he walked to his
Andrej [43]

Answer:

28 i think

Step-by-step explanation:

51+47=98

98-12 the ones that flew away that takes it to 86

86/3 the 3 balloons buntch than is 28

p.s. i mght of got some equations wrong but this is what i got

4 0
3 years ago
Find the number 17% of which is 27 more than 14% of it.
Kay [80]
The original number would be 900
5 0
3 years ago
The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation
MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And the sample variance is defined as:

s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is \sigma=2 then the variance would be \sigma^2 = 4 and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is \sigma=0.1 then the variance would be \sigma^2 = 0.01 and as we can see is lower than the standard deviation

7 0
3 years ago
Can someone help me out please I need help ?
Margarita [4]

Answer:

fglbef bgkfv dfg hti gri efgkrtgm ruigermfui5ygmruf thiptofktuigkrlv

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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