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Naily [24]
4 years ago
6

2. - 4x + 5y = 1 4x + 4y = 8

Mathematics
1 answer:
guapka [62]4 years ago
5 0

Answer:

(- 1, 1 )

Step-by-step explanation:

Given the 2 equations

- 4x + 5y = 1 → (1)

4x + 4y = 8 → (2)

Adding (1) and (2) term by term will eliminate the term in x

9y = 9 ( divide both sides by 9 )

y = 1

Substitute y = 1 into either (1) or (2) for corresponding value of x

Substituting in (1)

4x + 5(1) = 1, that is

4x + 5 = 1 ( subtract 5 from both sides )

4x = - 4 ( divide both sides by 4 )

x = - 1

Solution is (- 1, 1 )

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The axis of symmetry for the function f(x) = –2x2 + 4x + 1 is the line x = 1. Where is the vertex of the function located?
egoroff_w [7]

Answer:

(1, 3)

Step-by-step explanation:

You are given the h coordinate of the vertex as 1, but in order to find the k coordinate, you have to complete the square on the parabola.  The first few steps are as follows.  Set the parabola equal to 0 so you can solve for the vertex.  Separate the x terms from the constant by moving the constant to the other side of the equals sign.  The coefficient HAS to be a +1 (ours is a -2 so we have to factor it out).  Let's start there.  The first 2 steps result in this polynomial:

-2x^2+4x=-1.  Now we factor out the -2:

-2(x^2-2x)=-1.  Now we complete the square.  This process is to take half the linear term, square it, and add it to both sides.  Our linear term is 2x.  Half of 2 is 1, and 1 squared is 1.  We add 1 into the set of parenthesis.  But we actually added into the parenthesis is +1(-2).  The -2 out front is a multiplier and we cannot ignore it.  Adding in to both sides looks like this:

-2(x^2-2x+1)=-1-2.  Simplifying gives us this:

-2(x^2-2x+1)=-3

On the left we have created a perfect square binomial which reflects the h coordinate of the vertex.  Stating this binomial and moving the -3 over by addition and setting the polynomial equal to y:

-2(x-1)^2+3=y

From this form,

y=-a(x-h)^2+k

you can determine the coordinates of the vertex to be (1, 3)

5 0
3 years ago
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Is a positive integer raised to a negative power always positive
Evgesh-ka [11]

Answer:

Yes

Step-by-step explanation:

Many students gets confused with these exponential problems, they often get misguided but understand that there is nothing to be confused of.

When you have a negative number, you just take the reciprocal of the whole exponent number.

What is a reciprocal?

Let's take an integer for example, let's take the number 3.

The reciprocal for 3 is (1/3)

Let's take an other number, let's take 2/3

The reciprocal for 2/3 is (3/2)

In conclusion, we just reverse the denominator and the numerator or just switch it.

We take 3 as (3/1) and that is the reason, the reciprocal would be (1/3)

Now, coming to the negative integers. Taking an example:

(2)⁻¹

This would be become (1/2¹) = (1/2)

Hence, the result of a negative integer is positive but would be a fraction.

Hope I helped!


3 0
4 years ago
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