You first have to find the length of each side.
AB=4
BC=4
CD=4
AD=4
Since this is a quadrilateral, two sides will have the same length, in this case, they all do so you can pick any two sides.
4(4)=16.
Answer:
2x - 7y = -34.
Step-by-step explanation:
As the line we want is perpendicular to y= -7/2 x + 9 it's slope will be
-1 /(-7/2) = 2/7.
Now we find the point of intersection ofn the 2 given lines:
x + y = 10
3x - 4y = -12
Multiply the first equation by -3:
-3x - 3y = -30
Now add this last equation to the second one:
-7y = -42
y = 6
Plug y = 6 into the first equation:
x + 6 = 10
x = 4.
So the point of intersection is (4, 6) and the equation we want passes through this, so using the point-slope form of straight line we have:
y - 6 = 2/7(x - 4)
7y - 42 = 2(x - 4)
7y - 42 = 2x - 8
2x - 7y = -42 + 8
2x - 7y = -34
So whats the question? Sorry im confused
Answer:
-30
Step-by-step explanation:
Substituting values of a and b in equation
3(-5)+2(-6)-3
-15-12-3
-15-15
-30
